inserting data error code 23000 mysql pdo php

南楼画角 提交于 2020-06-09 04:29:08

问题


i have a table in my databse

i am trying to insert some data inside it

but i keep getting pdo error code 23000

i tried the query manually and it worked so the proplem isn't with the query

my code :

<?
include ('config.php');
$text=$_POST['text'];
if (!isset ($text)) exit();
$query=$db->prepare("INSERT INTO posts (post,userid,votes) VALUES (?,?,0)");
$query->bindValue(1,$text,PDO::PARAM_STR);
$query->bindValue(2,$id,PDO::PARAM_INT);
$re=$query->execute();
if ($re)
echo 'Added';
else die($query->errorcode()." ".$query->errorinfo());
?>

and config look like

<?
session_start();
try{
$db=new PDO ('mysql:host=localhost;dbname=test;charset=utf8','root','');
}
catch (PDOException $error) {
    echo $error->getmessage();
}
$id=$_SESSION['id'];
$username=$_SESSION['username'];
$password=$_SESSION['password'];
?>

回答1:


Did you check MySQL docs?

http://dev.mysql.com/doc/refman/5.0/en/error-messages-server.html#error_er_dup_key

Looks like you have a duplicate key in DB. My guess userid.

If you have an auto-increment on userid no need to pass it on creation.

Looking at your code it:

  1. Gets user from session
  2. Adds this user to DB

So if you run script more than once it'll give 23000 error.

Yes and how did userid got in to session?




回答2:


1062 error code means "dublicate entry"




回答3:


I suggest people with a 23000 error code to try :

print_r($dbObject->errorInfo()) ;

You're most likely to find the problem yourself as there's the error description.



来源:https://stackoverflow.com/questions/25815706/inserting-data-error-code-23000-mysql-pdo-php

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