Convert string date to ISO format date [duplicate]

问题

This question already has answers here:

Parsing a Date from a String in Java? (2 answers)

Convert Human Date (Local Time GMT) to date (2 answers)

How to get current moment in ISO 8601 format with date, hour, and minute? (22 answers)

Java SimpleDateFormat for time zone with a colon separator? (11 answers)

Closed last year.

I need to convert some string date to another format string date

String current = "Tue Apr 16 10:59:11 EDT 2019";

I want to get result date String in format ISO-8601 in accordance with the pattern - "yyyy-MM-dd'T'HH:mm:ss.SSSXX"

Could you please help me to implement this?

回答1:

Using Java8 DateTime API you can do something like following:

     //your input
     String date = "Tue Apr 16 10:59:11 EDT 2019";
     //create new formatter for parsing your input
     DateTimeFormatter formatter = DateTimeFormatter.ofPattern("EEE MMM d HH:mm:ss zzz yyyy", Locale.ENGLISH);
     //create new zonedDateTime from parsing an input with provided formatter
     ZonedDateTime zonedDateTime = ZonedDateTime.parse(date,formatter);

Get it in the format of your own:

     //format your zonedDateTime with a new provided pattern
     String test = zonedDateTime.format(DateTimeFormatter.ofPattern("yyyy-MM-dd'T'HH:mm:ss.SSSXX"));
     //print it
     System.out.println(test);

回答2:

There is a SimpleDateFormat in java, and there is a parse method in there

SimpleDateFormat format = new SimpleDateFormat("yyyy-MM-dd");

String dateString = format.format( new Date()   );
Date   date       = format.parse ( "2009-12-31" );      

回答3:

None of Java's time classes fully implement ISO 8601 but you can try with Java 8:

ZonedDateTime zp = ZonedDateTime.parse(string);
Date date = Date.from(zp.toInstant());
SimpleDateFormat dt1 = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss.SSSXX");
System.out.println(dt1.format(date));

来源：https://stackoverflow.com/questions/55703909/convert-string-date-to-iso-format-date