问题
Can any one help me to schedule a job in Crontab which will execute a simple Hive query on specific time and provide me the output in text/log file.
I have created a batch script to execute a select query , but getting error("Hive command not found") while executing it in Crontab. However same script is running fine through shell. Below is my script :
ip.sh
#!/bin/bash
echo "Starting of Job"
cd /home/hadoop/work/hive/bin
hive -e 'select * from mytest.empl'
echo "Script ends here"
Crontab: 10 * * * * /home/hadoop/work/ip.sh >> /home/hadoop/work/quryout.log 2>&1
After executing the Crontab , I am getting below message in log:
Output(Queryout.log): Starting Of Job hive command not found in ip.sh at line number 4 Script ends here
回答1:
Add these lines in your /home/hadoop/.bashrc
:
export HIVE_HOME=/home/hadoop/work/hive
export PATH=$PATH:$HIVE_HOME/bin
Now, change your script like this:
#!/bin/bash
echo "Starting of Job"
hive -e 'select * from mytest.empl'
echo "Script ends here"
回答2:
try this in shell script
/home/hadoop/work/hive/bin/hive -e 'select * from mytest.empl'
来源:https://stackoverflow.com/questions/30521650/to-schedule-a-hive-query-on-crontab