get field from json and assign to variable in bash script?

大城市里の小女人 提交于 2020-04-29 08:03:31

问题


I have a json store in jsonFile

{
  "key1": "aaaa bbbbb",
  "key2": "cccc ddddd"
}

I have code in mycode.sh:

#!/bin/bash
value=($(jq -r '.key1' jsonFile))
echo "$value"

After I run ./mycode.sh the result is aaaa but if I just run jq -r '.key1' jsonFile the result is aaaa bbbbb

Could anyone help me?


回答1:


With that line of code

value=($(jq -r '.key1' jsonFile))

you are assigning both values to an array. Note the outer parantheses () around the command. Thus you can access the values individually or echo the content of the entire array.

$ echo "${value[@]}"
aaaa bbbb

$ echo "${value[0]}"
aaaa

$ echo "${value[1]}"
bbbb

Since you echoed $value without specifying which value you want to get you only get the first value of the array.



来源:https://stackoverflow.com/questions/22528142/get-field-from-json-and-assign-to-variable-in-bash-script

标签
易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!