问题
I have a json store in jsonFile
{
"key1": "aaaa bbbbb",
"key2": "cccc ddddd"
}
I have code in mycode.sh
:
#!/bin/bash
value=($(jq -r '.key1' jsonFile))
echo "$value"
After I run ./mycode.sh
the result is aaaa
but if I just run jq -r '.key1' jsonFile
the result is aaaa bbbbb
Could anyone help me?
回答1:
With that line of code
value=($(jq -r '.key1' jsonFile))
you are assigning both values to an array. Note the outer parantheses ()
around the command.
Thus you can access the values individually or echo the content of the entire array.
$ echo "${value[@]}"
aaaa bbbb
$ echo "${value[0]}"
aaaa
$ echo "${value[1]}"
bbbb
Since you echoed $value
without specifying which value you want to get you only get the first value of the array.
来源:https://stackoverflow.com/questions/22528142/get-field-from-json-and-assign-to-variable-in-bash-script