convert result into JSON without structs using mongo-go-driver

十年热恋 提交于 2020-04-16 05:06:32

问题


I don't want to use structs before converting results into JSON. Let's say I have some results:

result, err := collection.Find(ctx, filter, options)

I can collect all results in docs variable and last result in doc variable:

    var doc bson.Raw
    var docs []bson.Raw    
    for result.Next(ctx) {
            document, err := result.DecodeBytes()
            if err != nil {
                log.Println(err)
            }
            doc = document
            docs = append(docs, doc)
        }

I can easily convert last result into JSON without using any structs:

var jsonDoc bson.M
err = bson.Unmarshal(doc, &jsonDoc)
return jsonDoc

I can't convert docs into JSON and use as a result in my Rest server.

Update 2019-01-17:

I'm using result in my REST server like this:

user.GET("/booking/customer/:id", func(c *gin.Context) {
    result := GetAllCustomerBookings(c.Param("id"))
    c.JSON(http.StatusOK, result)
})

so it can't be a loop through values. The question: how to convert []bson.Raw to []byte or bson.Raw. Let's imagine that now I have {JSON} in each value of array. I need one JSON like this: [{JSON}, {JSON}, ...].

Using nodejs was easier because I could send all records in one JSON document. Go and mongodb-go-driver needs to go through all records and I don't know how to build one JSON document.

Nodejs and mongodb equivalent:

router.get('/bookings/customer/:id', function (req, res, next) {
    db.Bookings.find({
        "booking.customer._id": {
            $eq: req.params.id
        }
    }).sort({
            "booking.arrival_date": -1
        },
        function (err, bookings) {
            if (err) {
                res.send(err);
            } else {
                res.json(bookings);
            }
        });
});

回答1:


This code works. After few hours of trying and thanks to good luck I managed to solve this issue. Maybe someone will explain this?

Instead of bson.Raw I used bson.M and result.Decode() instead of result.DecodeBytes() Now I have the same output as nodejs gives me.

 var docs []bson.M
    for result.Next(ctx) {
        var document bson.M
        err = result.Decode(&document)
        if err != nil {
            log.Println(err)
        }
        docs = append(docs, document)
    }
    return docs


来源:https://stackoverflow.com/questions/54224955/convert-result-into-json-without-structs-using-mongo-go-driver

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