Why is this Array.sort behaviour different in Chrome vs Node.js

问题

Problem

Let's make a basic list and sort it to make sure that 2 is ALWAYS first in the list. Simple enough, right?

[1, 2, 3].sort((a, b) => {
  if (a === 2) return -1;
  return 0;    
});

Chrome result: ✓

[2, 1, 3]

Node result: X

[1, 2, 3]

In order to get this behaviour in Node, you could - weirdly enough - look at the b parameter and make it return 1 if it's 2:

[1, 2, 3].sort((a, b) => {
  if (b === 2) return 1;
  return 0;    
});

With this implementation you get the opposite result; Chrome will be [1, 2, 3] and Node will be [2, 1, 3].

Questions

Do you have a logical explaination for this behaviour? Is my sorting function conceptually flawed? If so, how would you write this sorting behaviour?

回答1:

Do you have a logical explaination for this behaviour?

Browsers use different sorting methods. Therefore they possibly call the provided callback with different arguments in a different order. If your sort function is not consistent, the sorting won't be stable. This will lead to a wrong sort order (it also always would with different input arrays, so your sorting will never really work).

If so, how would you write this sorting behaviour?

Make sure that these two conditions apply to every possible input:

1) Two equal elements should not be sorted:

  sort(a, a) === 0

2) If the sort function gets called in inversed order, the result is also inversed:

  sort(a, b) - sort(b, a) === 0

In your case, both are not fullfilled:

  sort(2, 2) // 1 -> wrong!
  sort(2, 3) - sort(3, 2) // 1 -> wrong!

To write a stable sort, you have to look at a and b:

  function(a, b) {
    if(a === 2 && b === 2)
      return 0;
    if(a === 2)
      return 1;
    if(b === 2)
      return -1;
    return 0;
  }

Or to make that shorter:

  (a, b) => (a === 2) - (b === 2)

来源：https://stackoverflow.com/questions/55995255/why-is-this-array-sort-behaviour-different-in-chrome-vs-node-js

标签

javascript

node.js