C/C++ 语言中体验复杂度：汉诺塔问题（2）

/*  
 *Copyright (c) 2017, 烟台大学计算机学院  
 *All rights reserved.  
 *文件名称:main.cpp  
 *作    者：黄士胜  
 *完成日期：2017年9月13日  
 *版 本 号：v1.0  
 *  
 *问题描述：汉诺塔问题 
 *输入描述：盘子数目为 4 8 16 20 24
 *程序输出：见截屏  
 */    
#include <stdio.h>  
#define discCount 24  
long move(int, char, char,char);  
int main()  
{  
    long count;  
    count=move(discCount,'A','B','C');  
    printf("%d个盘子需要移动%ld次\n", discCount, count);  
    return 0;  
}  
  
long move(int n, char A, char B,char C)  
{  
    long c1,c2;  
    if(n==1)  
        return 1;  
    else  
    {  
        c1=move(n-1,A,C,B);  
        c2=move(n-1,B,A,C);  
        return c1+c2+1;  
    }  
}

#include <stdio.h>  
#define discCount 20  
long move(int, char, char,char);  
int main()  
{  
    long count;  
    count=move(discCount,'A','B','C');  
    printf("%d个盘子需要移动%ld次\n", discCount, count);  
    return 0;  
}  
  
long move(int n, char A, char B,char C)  
{  
    long c1,c2;  
    if(n==1)  
        return 1;  
    else  
    {  
        c1=move(n-1,A,C,B);  
        c2=move(n-1,B,A,C);  
        return c1+c2+1;  
    }  
}

  
#include <stdio.h>  
#define discCount 16
 
long move(int, char, char,char);  
int main()  
{  
    long count;  
    count=move(discCount,'A','B','C');  
    printf("%d个盘子需要移动%ld次\n", discCount, count);  
    return 0;  
}  
  
long move(int n, char A, char B,char C)  
{  
    long c1,c2;  
    if(n==1)  
        return 1;  
    else  
    {  
        c1=move(n-1,A,C,B);  
        c2=move(n-1,B,A,C);  
        return c1+c2+1;  
    }  
}

  
#include <stdio.h>  
#define discCount 8
 
long move(int, char, char,char);  
int main()  
{  
    long count;  
    count=move(discCount,'A','B','C');  
    printf("%d个盘子需要移动%ld次\n", discCount, count);  
    return 0;  
}  
  
long move(int n, char A, char B,char C)  
{  
    long c1,c2;  
    if(n==1)  
        return 1;  
    else  
    {  
        c1=move(n-1,A,C,B);  
        c2=move(n-1,B,A,C);  
        return c1+c2+1;  
    }  
}

  
#include <stdio.h>  
#define discCount 4
 
long move(int, char, char,char);  
int main()  
{  
    long count;  
    count=move(discCount,'A','B','C');  
    printf("%d个盘子需要移动%ld次\n", discCount, count);  
    return 0;  
}  
  
long move(int n, char A, char B,char C)  
{  
    long c1,c2;  
    if(n==1)  
        return 1;  
    else  
    {  
        c1=move(n-1,A,C,B);  
        c2=move(n-1,B,A,C);  
        return c1+c2+1;  
    }  
}