编写一个程序,开启 3 个线程,这三个线程的 ID 分别为 A、B、C,
每个线程将自己的 ID 在屏幕上打印 10 遍,要 求输出的结果必须按顺序显示
TestABCAlternate
package com.aff.juc;
import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;
public class TestABCAlternate {
public static void main(String[] args) {
AlternateDemo ad = new AlternateDemo();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 1; i <= 20; i++) {
ad.loopA(i);
}
}
},"A线程").start();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 1; i <= 20; i++) {
ad.loopB(i);
}
}
},"B线程").start();
new Thread(new Runnable() {
@Override
public void run() {
for (int i = 1; i <=20; i++) {
ad.loopC(i);
System.out.println("=============================");
}
}
},"C线程").start();
}
}
class AlternateDemo {
private int number = 1;
private Lock lock = new ReentrantLock();
private Condition condition1 = lock.newCondition();
private Condition condition2 = lock.newCondition();
private Condition condition3 = lock.newCondition();
// totalLoop :循环几轮
public void loopA(int totalLoop) {
lock.lock();
try {
// 1. 判断
if (number != 1) {
condition1.await();
}
// 2.打印
for (int i = 1; i <= 2; i++) {
System.out.println(Thread.currentThread().getName() + "\t" + i +"\t"+ "\t" + totalLoop);
}
// 3.唤醒
number = 2;
condition2.signal();// number为2 唤醒condition2
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
public void loopB(int totalLoop) {
lock.lock();
try {
// 1. 判断
if (number != 2) {
condition2.await();
}
// 2.打印
for (int i = 1; i <= 2; i++) {
System.out.println(Thread.currentThread().getName() + "\t" + "\t"+ i + "\t" + totalLoop);
}
// 3.唤醒
number = 3;
condition3.signal();// number为3 唤醒condition3
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
public void loopC(int totalLoop) {
lock.lock();
try {
// 1. 判断
if (number != 3) {
condition3.await();
}
// 2.打印
for (int i = 1; i <= 2; i++) {
System.out.println(Thread.currentThread().getName() + "\t" + "\t"+ i + "\t" + totalLoop);
}
// 3.唤醒
number = 1;
condition1.signal();// number为1 唤醒condition1
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}
}
来源:https://www.cnblogs.com/afangfang/p/12632559.html