MySQL(多表的表记录的查询)

爷,独闯天下 提交于 2020-03-18 12:57:45

一、外键约束

1、创建外键

---  每一个班主任会对应多个学生 , 而每个学生只能对应一个班主任

----主表
CREATE TABLE ClassCharger(

       id TINYINT PRIMARY KEY auto_increment,
       name VARCHAR (20),
       age INT ,
       is_marriged boolean  -- show create table ClassCharger: tinyint(1)
);

INSERT INTO ClassCharger (name,age,is_marriged) VALUES ("冰冰",12,0),
                                                       ("丹丹",14,0),
                                                       ("歪歪",22,0),
                                                       ("姗姗",20,0),
                                                       ("小雨",21,0);
----子表
CREATE TABLE Student(

       id INT PRIMARY KEY auto_increment,
       name VARCHAR (20),
       charger_id TINYINT,     --切记:作为外键一定要和关联主键的数据类型保持一致
       -- [ADD CONSTRAINT charger_fk_stu]FOREIGN KEY (charger_id) REFERENCES ClassCharger(id)
) ENGINE=INNODB;

INSERT INTO Student(name,charger_id) VALUES ("alvin1",2),
                                            ("alvin2",4),
                                            ("alvin3",1),
                                            ("alvin4",3),
                                            ("alvin5",1),
                                            ("alvin6",3),
                                            ("alvin7",2);
DELETE FROM ClassCharger WHERE name="冰冰";
INSERT student (name,charger_id) VALUES ("yuan",1);
-- 删除居然成功,可是 alvin3显示还是有班主任id=1的冰冰的;

-----------增加外键和删除外键---------

ALTER TABLE student  ADD CONSTRAINT abc
                     FOREIGN KEY(charger_id)
                     REFERENCES  classcharger(id);

ALTER TABLE student DROP FOREIGN KEY abc;

2、 INNODB支持的ON语句

--外键约束对子表的含义:   如果在父表中找不到候选键,则不允许在子表上进行insert/update

--外键约束对父表的含义:    在父表上进行update/delete以更新或删除在子表中有一条或多条对
                     -- 应匹配行的候选键时,父表的行为取决于:在定义子表的外键时指定的
                     -- on update/on delete子句


-----------------innodb支持的四种方式---------------------------------------

-----cascade方式 在父表上update/delete记录时,同步update/delete掉子表的匹配记录
-----外键的级联删除:如果父表中的记录被删除,则子表中对应的记录自动被删除--------

     FOREIGN KEY (charger_id) REFERENCES ClassCharger(id)
                              ON DELETE CASCADE


------set null方式 在父表上update/delete记录时,将子表上匹配记录的列设为null
   -- 要注意子表的外键列不能为not null

     FOREIGN KEY (charger_id) REFERENCES ClassCharger(id)
                              ON DELETE SET NULL


------Restrict方式 :拒绝对父表进行删除更新操作(了解)

------No action方式 在mysql中同Restrict,如果子表中有匹配的记录,则不允许对父表对应候选键
   -- 进行update/delete操作(了解)

二、多表查询

-- 准备两张表
-- company.employee
-- company.department

      create table employee(
      emp_id int auto_increment primary key not null,
      emp_name varchar(50),
      age int,
      dept_id int
      );

      insert into employee(emp_name,age,dept_id) values
        ('A',19,200),
        ('B',26,201),
        ('C',30,201),
        ('D',24,202),
        ('E',20,200),
        ('F',38,204);


    create table department(
       dept_id int,
       dept_name varchar(100)
      );

    insert into department values
      (200,'人事部'),
      (201,'技术部'),
      (202,'销售部'),
      (203,'财政部');

mysql> select * from employee;
+--------+----------+------+---------+
| emp_id | emp_name | age  | dept_id |
+--------+----------+------+---------+
|      1 | A        |   19 |     200 |
|      2 | B        |   26 |     201 |
|      3 | C        |   30 |     201 |
|      4 | D        |   24 |     202 |
|      5 | E        |   20 |     200 |
|      6 | F        |   38 |     204 |
+--------+----------+------+---------+
6 rows in set (0.00 sec)

mysql> select * from department;
+---------+-----------+
| dept_id | dept_name |
+---------+-----------+
|     200 | 人事部    |
|     201 | 技术部    |
|     202 | 销售部    |
|     203 | 财政部    |
+---------+-----------+
4 rows in set (0.01 sec)
准备表和数据

1、多表查询之连接查询

1.笛卡尔积查询

mysql> SELECT * FROM employee,department;

--        select employee.emp_id,employee.emp_name,employee.age,
--        department.dept_name from employee,department;

+--------+----------+------+---------+---------+-----------+
| emp_id | emp_name | age  | dept_id | dept_id | dept_name |
+--------+----------+------+---------+---------+-----------+
|      1 | A        |   19 |     200 |     200 | 人事部    |
|      1 | A        |   19 |     200 |     201 | 技术部    |
|      1 | A        |   19 |     200 |     202 | 销售部    |
|      1 | A        |   19 |     200 |     203 | 财政部    |
|      2 | B        |   26 |     201 |     200 | 人事部    |
|      2 | B        |   26 |     201 |     201 | 技术部    |
|      2 | B        |   26 |     201 |     202 | 销售部    |
|      2 | B        |   26 |     201 |     203 | 财政部    |
|      3 | C        |   30 |     201 |     200 | 人事部    |
|      3 | C        |   30 |     201 |     201 | 技术部    |
|      3 | C        |   30 |     201 |     202 | 销售部    |
|      3 | C        |   30 |     201 |     203 | 财政部    |
|      4 | D        |   24 |     202 |     200 | 人事部    |
|      4 | D        |   24 |     202 |     201 | 技术部    |
|      4 | D        |   24 |     202 |     202 | 销售部    |
|      4 | D        |   24 |     202 |     203 | 财政部    |
|      5 | E        |   20 |     200 |     200 | 人事部    |
|      5 | E        |   20 |     200 |     201 | 技术部    |
|      5 | E        |   20 |     200 |     202 | 销售部    |
|      5 | E        |   20 |     200 |     203 | 财政部    |
|      6 | F        |   38 |     204 |     200 | 人事部    |
|      6 | F        |   38 |     204 |     201 | 技术部    |
|      6 | F        |   38 |     204 |     202 | 销售部    |
|      6 | F        |   38 |     204 |     203 | 财政部    |
+--------+----------+------+---------+---------+-----------+

2.内连接

-- 查询两张表中都有的关联数据,相当于利用条件从笛卡尔积结果中筛选出了正确的结果。

  select * from employee,department where employee.dept_id = department.dept_id;
--select * from employee inner join department on employee.dept_id = department.dept_id;

      +--------+----------+------+---------+---------+-----------+
      | emp_id | emp_name | age  | dept_id | dept_id | dept_name |
      +--------+----------+------+---------+---------+-----------+
      |      1 | A        |   19 |     200 |     200 | 人事部    |
      |      2 | B        |   26 |     201 |     201 | 技术部    |
      |      3 | C        |   30 |     201 |     201 | 技术部    |
      |      4 | D        |   24 |     202 |     202 | 销售部    |
      |      5 | E        |   20 |     200 |     200 | 人事部    |
      +--------+----------+------+---------+---------+-----------+

3.外连接

--(1)左外连接:在内连接的基础上增加左边有右边没有的结果

 select * from employee left join department on employee.dept_id = department.dept_id;

     +--------+----------+------+---------+---------+-----------+
    | emp_id | emp_name | age  | dept_id | dept_id | dept_name |
    +--------+----------+------+---------+---------+-----------+
    |      1 | A        |   19 |     200 |     200 | 人事部    |
    |      5 | E        |   20 |     200 |     200 | 人事部    |
    |      2 | B        |   26 |     201 |     201 | 技术部    |
    |      3 | C        |   30 |     201 |     201 | 技术部    |
    |      4 | D        |   24 |     202 |     202 | 销售部    |
    |      6 | F        |   38 |     204 |    NULL | NULL      |
    +--------+----------+------+---------+---------+-----------+

 --(2)右外连接:在内连接的基础上增加右边有左边没有的结果

 select * from employee RIGHT JOIN department on employee.dept_id = department.dept_id;

        +--------+----------+------+---------+---------+-----------+
        | emp_id | emp_name | age  | dept_id | dept_id | dept_name |
        +--------+----------+------+---------+---------+-----------+
        |      1 | A        |   19 |     200 |     200 | 人事部    |
        |      2 | B        |   26 |     201 |     201 | 技术部    |
        |      3 | C        |   30 |     201 |     201 | 技术部    |
        |      4 | D        |   24 |     202 |     202 | 销售部    |
        |      5 | E        |   20 |     200 |     200 | 人事部    |
        |   NULL | NULL     | NULL |    NULL |     203 | 财政部    |
        +--------+----------+------+---------+---------+-----------+

 --(3)全外连接:在内连接的基础上增加左边有右边没有的和右边有左边没有的结果

    -- mysql不支持全外连接 full JOIN
    -- mysql可以使用此种方式间接实现全外连接
    
   select * from employee RIGHT JOIN department on employee.dept_id = department.dept_id
   UNION
   select * from employee LEFT JOIN department on employee.dept_id = department.dept_id;
        +--------+----------+------+---------+---------+-----------+
        | emp_id | emp_name | age  | dept_id | dept_id | dept_name |
        +--------+----------+------+---------+---------+-----------+
        |      1 | A        |   19 |     200 |     200 | 人事部    |
        |      2 | B        |   26 |     201 |     201 | 技术部    |
        |      3 | C        |   30 |     201 |     201 | 技术部    |
        |      4 | D        |   24 |     202 |     202 | 销售部    |
        |      5 | E        |   20 |     200 |     200 | 人事部    |
        |   NULL | NULL     | NULL |    NULL |     203 | 财政部    |
        |      6 | F        |   38 |     204 |    NULL | NULL      |
        +--------+----------+------+---------+---------+-----------+

      -- 注意 union与union all的区别:union会去掉相同的纪录

2、多表查询之复合条件连接查询

-- 查询员工年龄大于等于25岁的部门

    SELECT DISTINCT department.dept_name
    FROM employee,department
    WHERE employee.dept_id = department.dept_id
    AND age>25;


--以内连接的方式查询employee和department表,并且以age字段的升序方式显示

    select employee.emp_id,employee.emp_name,employee.age,department.dept_name
    from employee,department
    where employee.dept_id = department.dept_id
    order by age asc;

3、多表查询之子查询

-- 子查询是将一个查询语句嵌套在另一个查询语句中。
-- 内层查询语句的查询结果,可以为外层查询语句提供查询条件。
-- 子查询中可以包含:IN、NOT IN、ANY、ALL、EXISTS 和 NOT EXISTS等关键字
-- 还可以包含比较运算符:= 、 !=、> 、<等

-- 1. 带IN关键字的子查询

   ---查询employee表,但dept_id必须在department表中出现过

   select * from employee
            where dept_id IN
            (select dept_id from department);

+--------+----------+------+---------+
| emp_id | emp_name | age  | dept_id |
+--------+----------+------+---------+
|      1 | A        |   19 |     200 |
|      2 | B        |   26 |     201 |
|      3 | C        |   30 |     201 |
|      4 | D        |   24 |     202 |
|      5 | E        |   20 |     200 |
+--------+----------+------+---------+
5 rows in set (0.01 sec)

-- 2. 带比较运算符的子查询
      --      =、!=、>、>=、<、<=、<>

     -- 查询员工年龄大于等于25岁的部门
     select dept_id,dept_name from department
           where dept_id IN
          (select DISTINCT dept_id from employee where age>=25);

-- 3. 带EXISTS关键字的子查询

-- EXISTS关字键字表示存在。在使用EXISTS关键字时,内层查询语句不返回查询的记录。
-- 而是返回一个真假值。Ture或False
-- 当返回Ture时,外层查询语句将进行查询;当返回值为False时,外层查询语句不进行查询

     select * from employee
              WHERE EXISTS
              (SELECT dept_name from department where dept_id=203);

      --department表中存在dept_id=203,Ture


     select * from employee
                WHERE EXISTS
              (SELECT dept_name from department where dept_id=205);

     -- Empty set (0.00 sec)


    ps:  create table t1(select * from t2);

 三、课后练习

练习一:

1、将所有的课程的名称以及对应的任课老师姓名打印出来

SELECT cid,cname,tname FROM course LEFT JOIN teacher on course.teacher_id=teacher.tid;

2、查询学生表中男女生各有多少人

SELECT gender,COUNT(gender) 人数 FROM student GROUP BY gender;

3、查询物理成绩等于100的学生的姓名

SELECT sid,sname FROM student WHERE sid in (SELECT student_id FROM score WHERE course_id=(SELECT cid FROM course WHERE cname='物理') and num=100);

4、查询平均成绩大于八十分的同学的姓名和平均成绩

SELECT sname,AVG(num) FROM student,score WHERE student.sid=score.student_id GROUP BY student_id HAVING AVG(num)>80;

5、查询所有学生的学号,姓名,选课数,总成绩

SELECT student_id 学号 ,sname 姓名,COUNT(course_id) 选课数,SUM(num) 总成绩 FROM student,score WHERE student.sid=student_id GROUP BY student_id;

6、查询姓李老师的个数

SELECT COUNT(tname) 姓李老师个数 from teacher WHERE tname like '李%';

7、查询没有报李平老师课的学生姓名

SELECT sid,sname FROM student WHERE sid NOT IN (SELECT distinct student_id from score LEFT JOIN student on student_id=student.sid WHERE course_id in (SELECT cid from course,teacher WHERE teacher_id=tid and tname='李平老师'));

mysql> select sid,sname from student where sid not in (SELECT distinct student_id from score where course_id in (SELECT cid from course,teacher WHERE teacher_id=tid and tname='李平老师'));

8、查询物理课程比生物课程高的学生的学号

SELECT A.student_id FROM
(SELECT * FROM score WHERE course_id=(SELECT cid FROM course WHERE cname='物理'))A
INNER JOIN
(SELECT * FROM score WHERE course_id=(SELECT cid FROM course WHERE cname='生物')) B ON A.student_id = B.student_id WHERE A.num>B.num

9、查询没有同时选修物理课程和体育课程的学生姓名

SELECT sid,sname from student WHERE sid NOT IN (SELECT student_id from score WHERE course_id in (2,3) GROUP BY student_id HAVING COUNT(student_id)=2);

10、查询挂科超过两门(包括两门)的学生姓名和班级

SELECT sname,caption FROM student,class WHERE class_id=cid and sid IN (SELECT student_id FROM score WHERE num<60 GROUP BY student_id HAVING COUNT(student_id)>=2);

11 、查询选修了所有课程的学生姓名

SELECT sname FROM student WHERE sid in (SELECT student_id FROM score  GROUP BY student_id HAVING COUNT(course_id)=(SELECT COUNT(cid) FROM course));

12、查询李平老师教的课程的所有成绩记录

SELECT sid,sname,cname,num FROM  student RIGHT JOIN (SELECT student_id,cname,num FROM  score,course WHERE course_id=cid AND course_id in (SELECT cid from course,teacher WHERE teacher_id=tid and tname='李平老师')) ls on ls.student_id=student.sid;

13、查询选课学生都选修了的课程号和课程名

SELECT cid,cname FROM course WHERE cid =(SELECT course_id from score GROUP BY course_id HAVING COUNT(student_id)=(select count(distinct student_id) from score))

练习二:

14、查询每门课程被选修的次数

SELECT course_id,cname,COUNT(course_id) 被选课次数 FROM score,course WHERE cid=course_id GROUP BY course_id;

15、查询只选修了一门课程的学生姓名和学号

SELECT sid,sname FROM student WHERE sid =(SELECT student_id FROM score GROUP BY student_id HAVING COUNT(course_id)=1);

16、查询所有学生考出的成绩并按从高到低排序(成绩去重)

SELECT DISTINCT num FROM score ORDER BY num DESC;

17、查询平均成绩大于85的学生姓名和平均成绩

 SELECT sname,AVG(num) FROM score,student WHERE student_id =student.sid GROUP BY student_id HAVING AVG(num)>85;

18、查询生物成绩不及格的学生姓名和对应生物分数

SELECT sname,num FROM score,student WHERE student_id=student.sid AND course_id=(SELECT cid FROM course WHERE cname='生物') and num<60;

19、查询在所有选修了李平老师课程的学生中,这些课程(李平老师的课程,不是所有课程)平均成绩最高的学生姓名

SELECT student_id,sname,AVG(num) FROM score,student WHERE student_id=student.sid AND course_id in (SELECT cid FROM course WHERE teacher_id =( SELECT tid FROM teacher WHERE tname like '李平%')) GROUP BY student_id  ORDER BY AVG(num) DESC LIMIT 1;

20、查询每门课程成绩最好的前两名学生姓名

 

21、查询不同课程但成绩相同的学号,课程号,成绩

SELECT * FROM score WHERE student_id IN (SELECT student_id FROM score GROUP BY num,student_id HAVING COUNT(student_id)>=2);

22、查询没学过“李平”老师课程的学生姓名以及选修的课程名称;

SELECT * from score WHERE student_id NOT IN (select distinct student_id from score where course_id in (SELECT cid FROM
course WHERE teacher_id =( SELECT tid FROM teacher WHERE tname like '李平%')));

23、查询所有选修了学号为1的同学选修过的一门或者多门课程的同学学号和姓名;

SELECT sid,sname FROM student WHERE sid IN (SELECT DISTINCT student_id FROM score WHERE course_id IN (SELECT course_id from score WHERE student_id=1) AND student_id!=1);

24、任课最多的老师中学生单科成绩最高的学生姓名

SELECT sname FROM student WHERE sid IN (SELECT student_id FROM score,(SELECT course_id,MAX(num) 最大值 FROM score WHERE course_id in (SELECT cid FROM course WHERE teacher_id=(SELECT teacher_id FROM course GROUP BY teacher_id ORDER BY COUNT(cid) DESC LIMIT 1)) GROUP BY course_id HAVING max(num)) A WHERE A.最大值=score.num AND score.course_id=A.course_id);

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