Get name of calling function in zsh

问题

I want to get function caller name in shell script sometime, in bash it works with ${FUNCNAME[1]}

${FUNCNAME[1]} is a (caller name)

${FUNCNAME[0]} is c (current name)

but it not work in zsh

ie i want to know which function call me in function c

function a(){
    c
}

function b(){
    c
}

function c(){
     #if a call me; then...
     #if b call me; then...
}

回答1:

The function call stack is in the variable $funcstack[].

$ f(){echo $funcstack[1];}
$ f
f

回答2:

Generic solution

• Works whether array indexing starts at 0 (option KSH_ARRAYS) or 1 (default)
• Works in both zsh and bash

---

# Print the name of the function calling me
function func_name () {
  if [[ -n $BASH_VERSION ]]; then
    printf "%s\n" "${FUNCNAME[1]}"
  else  # zsh
    # Use offset:length as array indexing may start at 1 or 0
    printf "%s\n" "${funcstack[@]:1:1}"
  fi
}

Edge case

The difference between bash and zsh is that when calling this function from a sourced file, bash will say source while zsh will say the name of the file being sourced.

来源：https://stackoverflow.com/questions/31426565/get-name-of-calling-function-in-zsh