Reading POST data from html form sent to serversocket

倾然丶 夕夏残阳落幕 提交于 2019-11-27 16:40:38

问题


i try to write simplest possible server app in Java, displaying html form with textarea input, which after submitting gives me possibility to parse xml typed in that textarea. For now i build simple serversocket based server like that:

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.net.ServerSocket;
import java.net.Socket;

public class WebServer {

  protected void start() {
    ServerSocket s;
    String gets = "";
    System.out.println("Start on port 80");
    try {
      // create the main server socket
      s = new ServerSocket(80);
    } catch (Exception e) {
      System.out.println("Error: " + e);
      return;
    }

    System.out.println("Waiting for connection");
    for (;;) {
      try {
        // wait for a connection
        Socket remote = s.accept();
        // remote is now the connected socket
        System.out.println("Connection, sending data.");
        BufferedReader in = new BufferedReader(new InputStreamReader(
            remote.getInputStream()));
        PrintWriter out = new PrintWriter(remote.getOutputStream());

        String str = ".";

        while (!str.equals("")) {
          str = in.readLine();
          if (str.contains("GET")){
            gets = str;
            break;
          }
        }

        out.println("HTTP/1.0 200 OK");
        out.println("Content-Type: text/html");
        out.println("");
        // Send the HTML page
        String method = "get";
        out.print("<html><form method="+method+">");
        out.print("<textarea name=we></textarea></br>");
        out.print("<input type=text name=a><input type=submit></form></html>");
        out.println(gets);
        out.flush();

        remote.close();
      } catch (Exception e) {
        System.out.println("Error: " + e);
      }
    }
  }

  public static void main(String args[]) {
    WebServer ws = new WebServer();
    ws.start();
  }
}

After form (textarea with xml and one additional text input) is submitted in 'gets' String-type variable I have Urlencoded values of my variables (also displayed on the screen, it looks like that:

gets = GET /?we=%3Cnetwork+ip_addr%3D%2210.0.0.0%2F8%22+save_ip%3D%22true%22%3E%0D%0A%3Csubnet+interf_used%3D%22200%22+name%3D%22lan1%22+%2F%3E%0D%0A%3Csubnet+interf_used%3D%22254%22+name%3D%22lan2%22+%2F%3E%0D%0A%3C%2Fnetwork%3E&a=fooBar HTTP/1.1 

What can i do to change GET to POST method (if i simply change it in form and than put " if (str.contains("POST")){" it gives me string like

gets = POST / HTTP/1.1

with no variables. And after that, how i can use xml from my textarea field (called 'we')?


回答1:


As there is a blank line following the headers, here is my relatively simple way of getting the post payload data, after having read the header information using the readLine() method of BufferedReader.

//socket is an instance of Socket
InputStream is = socket.getInputStream();
InputStreamReader isReader = new InputStreamReader(is);
BufferedReader br = new BufferedReader(isReader);

//code to read and print headers
String headerLine = null;
    while((headerLine = br.readLine()).length() != 0){
        System.out.println(headerLine);
    }

//code to read the post payload data
StringBuilder payload = new StringBuilder();
        while(br.ready()){
            payload.append((char) br.read());
            }
System.out.println("Payload data is: "+payload.toString())



回答2:


This is my implementation for read POST body:

try {
    Socket socket = params[0];
    BufferedReader in = new BufferedReader(new InputStreamReader(socket.getInputStream()));
    BufferedWriter out = new BufferedWriter(new OutputStreamWriter(socket.getOutputStream()));
    // read request
    String line;
    line = in.readLine();
    StringBuilder raw = new StringBuilder();
    raw.append("" + line);
    boolean isPost = line.startsWith("POST");
    int contentLength = 0;
    while (!(line = in.readLine()).equals("")) {
        raw.append('\n' + line);
        if (isPost) {
            final String contentHeader = "Content-Length: ";
            if (line.startsWith(contentHeader)) {
                contentLength = Integer.parseInt(line.substring(contentHeader.length()));
            }
        }
    }
    StringBuilder body = new StringBuilder();
    if (isPost) {
        int c = 0;
        for (int i = 0; i < contentLength; i++) {
            c = in.read();
            body.append((char) c);
            Log.d("JCD", "POST: " + ((char) c) + " " + c);
        }
    }
    raw.append(body.toString());
    publishProgress(raw.toString());
    // send response
    out.write("HTTP/1.1 200 OK\r\n");
    out.write("Content-Type: text/html\r\n");
    out.write("\r\n");
    out.write(new Date().toString());
    if (isPost) {
        out.write("<br><u>" + body.toString() + "</u>");
    } else {
        out.write("<form method='POST'>");
        out.write("<input name='name' type='text'/>");
        out.write("<input type='submit'/>");
        out.write("</form>");
    }
    //
    // do not in.close();
    out.flush();
    out.close();
    socket.close();
    //
} catch (Exception e) {
    e.printStackTrace();
    StringWriter sw = new StringWriter();
    e.printStackTrace(new PrintWriter(sw));
    publishProgress('\n' + sw.toString());
}

I do it for android and publishProgres in my case means:

protected void onProgressUpdate(String... values) {
        super.onProgressUpdate(values);
        instance.logTextView.append(values[0]);
    }



回答3:


A typical HTTP POST request looks like this:

POST / HTTP/1.1
Host: www.example.com
Accept: text/html,*/*;q=0.5
User-Agent: BrowserName/1.0
Referer: http://www.example.com/
Content-type: application/x-www-form-urlencoded; charset=utf-8

foo=1&bar=2

The first line contains the method (typically GET or POST, but there's more, like HEAD, PUT, DELETE), the request URI, and the protocol version. Then there are a number of request headers, which may not be so important for a simple server. If the method is one that takes a request body (POST and PUT), then after the headers there's a blank line followed by the request body. In the case of a POST from an HTML form, the body will consists of key=value pairs for all form elements, joined by &. The values will be %-encoded.

You just need to take care of properly parsing the entire request.

You should be aware that line endings in HTTP are supposed to be Windows-style (\r\n). The readline() method might interpret this as two linebreaks, so it might look like there's an empty line between each of the real lines.




回答4:


POST data is not in the first line. Print all lines and you'll see. It's actually immediately after a blank line.




回答5:


From this -

We need to first read headers and then read again from the same BufferedReader using actual content length provided in the header section :-

BufferedReader in = new BufferedReader(new InputStreamReader(is));
String line;
line = in.readLine();
while ((line = in.readLine()) != null && (line.length() != 0)) {
    System.out.println("HTTP-HEADER: " + line);
    if (line.indexOf("Content-Length:") > -1) {
    postDataI = new Integer(
        line.substring(
            line.indexOf("Content-Length:") + 16,
            line.length())).intValue();
    }
}
String postData = "";
// read the post data
if (postDataI > 0) {
    char[] charArray = new char[postDataI];
    in.read(charArray, 0, postDataI);
    postData = new String(charArray);
}

HTH



来源:https://stackoverflow.com/questions/3033755/reading-post-data-from-html-form-sent-to-serversocket

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