我曾经使用perl -c programfile来检查Perl程序的语法,然后退出而不执行它。 是否有相同的方法为Python脚本执行此操作?
#1楼
也许有用的在线检查PEP8: http ://pep8online.com/
#2楼
由于某种原因(我是一个py新手......)-m电话没有用...
所以这里是一个bash包装器功能...
# ---------------------------------------------------------
# check the python synax for all the *.py files under the
# <<product_version_dir/sfw/python
# ---------------------------------------------------------
doCheckPythonSyntax(){
doLog "DEBUG START doCheckPythonSyntax"
test -z "$sleep_interval" || sleep "$sleep_interval"
cd $product_version_dir/sfw/python
# python3 -m compileall "$product_version_dir/sfw/python"
# foreach *.py file ...
while read -r f ; do \
py_name_ext=$(basename $f)
py_name=${py_name_ext%.*}
doLog "python3 -c \"import $py_name\""
# doLog "python3 -m py_compile $f"
python3 -c "import $py_name"
# python3 -m py_compile "$f"
test $! -ne 0 && sleep 5
done < <(find "$product_version_dir/sfw/python" -type f -name "*.py")
doLog "DEBUG STOP doCheckPythonSyntax"
}
# eof func doCheckPythonSyntax
#3楼
您可以使用这些工具:
#4楼
import sys
filename = sys.argv[1]
source = open(filename, 'r').read() + '\n'
compile(source, filename, 'exec')
将其保存为checker.py并运行python checker.py yourpyfile.py 。
#5楼
这是使用ast模块的另一个解决方案:
python -c "import ast; ast.parse(open('programfile').read())"
要在Python脚本中干净地完成它:
import ast, traceback
filename = 'programfile'
with open(filename) as f:
source = f.read()
valid = True
try:
ast.parse(source)
except SyntaxError:
valid = False
traceback.print_exc() # Remove to silence any errros
print(valid)
来源:oschina
链接:https://my.oschina.net/stackoom/blog/3191175