iOS中日期和字符串的相互转化

梦想与她 提交于 2020-03-02 12:41:29

例1、 从服务器段获取到的字符串转化为时间如:

//网络请求获取的数据

    NSString *time = @"495946429";
    
    NSInteger num = [time integerValue];
    
    NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
    
    [formatter setDateStyle:NSDateFormatterMediumStyle];
    
    [formatter setTimeStyle:NSDateFormatterShortStyle];
    
    [formatter setDateFormat:@"YYYY-MM-dd"];
    
    NSDate *confromTimesp = [NSDate dateWithTimeIntervalSince1970:num];
    
    NSString *confromTimespStr = [formatter stringFromDate:confromTimesp];
    
    NSLog(@"%@",confromTimespStr);

转化之后结果为:1985-09-19

 

例2、如何如何将一个字符串如“ 20110826134106”装化为任意的日期时间格式,下面列举两种类型:

    NSString *string = @"20110826134106";
    
    NSDateFormatter *inputFormatter= [[NSDateFormatter alloc] init];
    
    [inputFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
    
    [inputFormatter setDateFormat:@"yyyyMMddHHmmss"];
    
    NSDate *inputDate = [inputFormatter dateFromString:string];
    
    NSLog(@"date= %@", inputDate);
    
    
    
    NSDateFormatter *outputFormatter= [[NSDateFormatter alloc] init];
    
    [outputFormatter setLocale:[NSLocale currentLocale]];
    
    [outputFormatter setDateFormat:@"yyyy年MM月dd日 HH时mm分ss秒"];
    
    NSString *str= [outputFormatter stringFromDate:inputDate];
    
    NSLog(@"testDate:%@",str);

两次打印的结果为:

date= 2011-08-26 05:41:06 +0000

testDate:20110826 134106

 

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