例1、 从服务器段获取到的字符串转化为时间如:
//网络请求获取的数据
NSString *time = @"495946429";
NSInteger num = [time integerValue];
NSDateFormatter *formatter = [[NSDateFormatter alloc]init];
[formatter setDateStyle:NSDateFormatterMediumStyle];
[formatter setTimeStyle:NSDateFormatterShortStyle];
[formatter setDateFormat:@"YYYY-MM-dd"];
NSDate *confromTimesp = [NSDate dateWithTimeIntervalSince1970:num];
NSString *confromTimespStr = [formatter stringFromDate:confromTimesp];
NSLog(@"%@",confromTimespStr);
转化之后结果为:1985-09-19
例2、如何如何将一个字符串如“ 20110826134106”装化为任意的日期时间格式,下面列举两种类型:
NSString *string = @"20110826134106";
NSDateFormatter *inputFormatter= [[NSDateFormatter alloc] init];
[inputFormatter setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
[inputFormatter setDateFormat:@"yyyyMMddHHmmss"];
NSDate *inputDate = [inputFormatter dateFromString:string];
NSLog(@"date= %@", inputDate);
NSDateFormatter *outputFormatter= [[NSDateFormatter alloc] init];
[outputFormatter setLocale:[NSLocale currentLocale]];
[outputFormatter setDateFormat:@"yyyy年MM月dd日 HH时mm分ss秒"];
NSString *str= [outputFormatter stringFromDate:inputDate];
NSLog(@"testDate:%@",str);
两次打印的结果为:
date= 2011-08-26 05:41:06 +0000
testDate:2011年08月26日 13时41分06秒
来源:oschina
链接:https://my.oschina.net/u/1451688/blog/707506