905. Sort Array By Parity

Question

905. Sort Array By Parity

Solution

题目大意：数组排序，偶数放前，奇数在后，偶数的数之间不用管顺序，奇数的数之间也不用管顺序

思路：建两个list，一个放偶数，一个放奇数，最后将两个list合并，转化为数组返回

Java实现：

public int[] sortArrayByParity(int[] A) {
    List<Integer> evenList = new ArrayList<>();
    List<Integer> oddList = new ArrayList<>();
    for (int i = 0; i < A.length; i++) {
        if (A[i] % 2 == 0) evenList.add(A[i]);
        else oddList.add(A[i]);
    }
    evenList.addAll(oddList);
    int[] retArr = new int[A.length];
    for (int i = 0; i < evenList.size(); i++) {
        retArr[i] = evenList.get(i);
    }
    return retArr;
}

来源：oschina

链接：https://my.oschina.net/u/159293/blog/2066188