SQlite query to update column and replace a value

问题

I want to update a column that contains a string like 12,43,433 I want to only replace 43 with another number say 54 so that the column value becomes 12,54,433.

How can I do that??

回答1:

Storing lists as strings is a very bad idea. SQL has a great data structure for storing lists. It is called a table, not a string. The proper way to store lists is to use a junction table.

Sometimes we are stuck with other people's really bad design decisions. If so, you can do:

update t
    set col = trim(replace(',' || col || ',', ',43,', ',54,'), ',')
    where ',' || col || ',' like '%,43,%';

Notes:

• This works regardless of where the "43" appears in the string (including at the beginning and end).
• This maintains the format of the string with no commas at the beginning and end.
• This only attempts to update rows that have the particular elements in the list.

Use of such a query should really be a stopgap while you figure out how to fix the data structure.

回答2:

You can use REPLACE() function like this:

UPDATE YourTable a
SET a.StringColumn = REPLACE(a.StringColumn,',43,',',54,')
WHERE a.StringColumn like '%,43,%'

来源：https://stackoverflow.com/questions/35480041/sqlite-query-to-update-column-and-replace-a-value