the number of lines (rows) of pixels a and the number of columns of pixels b

我是研究僧i 提交于 2020-02-08 02:27:53

A big company decided to launch a new series of rectangular displays, and decided that the display must have exactly n pixels.

Your task is to determine the size of the rectangular display — the number of lines (rows) of pixels a and the number of columns of pixels b, so that:

there are exactly n pixels on the display;
the number of rows does not exceed the number of columns, it means a ≤ b;
the difference b - a is as small as possible.
Input
The first line contains the positive integer n (1 ≤ n ≤ 106) — the number of pixels display should have.

Output
Print two integers — the number of rows and columns on the display.

Examples
Input
8
Output
2 4
Input
64
Output
8 8
Input
5
Output
1 5
Input
999999
Output
999 1001
Note
In the first example the minimum possible difference equals 2, so on the display should be 2 rows of 4 pixels.

In the second example the minimum possible difference equals 0, so on the display should be 8 rows of 8 pixels.

In the third example the minimum possible difference equals 4, so on the display should be 1 row of 5 pixels.

#include<bits/stdc++.h>
using namespace std;
int main()
{
    std::ios::sync_with_stdio(false);
    int n;
    cin>>n;
    int a,b;
    for(int i=1;i*i<=n;i++)
    {
        if(n%i==0)
        {
            a=i;
            b=n/i;
        }
    }
    cout<<a<<" "<<b<<endl;
   return 0;
}

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