demo:
#include <iostream>
#include <iomanip>
using namespace std;
int main() {
char *ch;
void *in;
int i=0x11223344,j;
in=&i;
ch=(char*)in;
for(j=0;j<4;j++)
{
/*setiosflags(ios_base::hex)不起作用*/
cout<<hex<<(int)*(ch+j)<<endl;//hex输出必须对应int类型,否则输出ASCII码
}
return 0;
}
来源:CSDN
作者:dragon_cdut
链接:https://blog.csdn.net/renlonggg/article/details/104172129