Throw exception from constructor initializer

问题

What is the best way to throw exception from the constructor initializer?

For example:

class C {
  T0 t0; // can be either valid or invalid, but does not throw directly
  T1 t1; // heavy object, do not construct if t0 is invalid,  by throwing before
  C(int n)
    : t0(n), // throw exception if t0(n) is not valid
      t1() {}
};

I thought maybe making wrapper, e.g. t0(throw_if_invalid(n)).

What is the practice to handle such cases?

回答1:

There are multiple ways of going about this, I think. From what I understand, n can only take on a specific range of numbers. For that, you might prevent the constructor from even being run:

template <typename T, T Min, T Max>
class ranged_type_c
{
public:
    typedef T value_type;

    ranged_type_c(const value_type& pX) :
    mX(pX)
    {
        check_value();
    }

    const value_type& get(void) const
    {
        return mX;
    }

    operator const value_type&(void) const
    {
        return get();
    }

    // non-const overloads would probably require a proxy
    // of some sort, to ensure values remain valid

private:
    void check_value(void)
    {
        if (mX < Min || mX > Max)
            throw std::range_error("ranged value out of range");
    }

    value_type mX;
};

Could be more fleshed out, but that's the idea. Now you can clamp the range:

struct foo_c
{
    foo_c(ranged_value_c<int, 0, 100> i) :
    x(i)
    {}

    int x;
};

If you pass a value that does not lie from 0-100, the above would throw.

At runtime, I think your original idea was best:

template <typename T>
const T& check_range(const T& pX, const T& pMin, const T& pMax)
{
    if (pX < pMin || pX > pMax)
        throw std::range_error("ranged value out of range");

    return pValue;
}

struct foo
{
    foo(int i) :
    x(check_range(i, 0, 100))
    {}

    int x;
}

And that's it. Same as above, but 0 and 100 can be replaced with a call to some function that returns the valid minimum and maximum.

If you do end up using a function call to get valid ranges (recommended, to keep clutter to a minimum and organization higher), I'd add an overload:

template <typename T>
const T& check_range(const T& pX, const std::pair<T, T>& pRange)
{
    return check_range(pX, pRange.first, pRange.second); // unpack
}

To allow stuff like this:

std::pair<int, int> get_range(void)
{
    // replace with some calculation
    return std::make_pair(0, 100);
}

struct foo
{
    foo(int i) :
    x(check_range(i, get_range()))
    {}

    int x;
}

If I were to choose, I'd pick the runtime methods even if the range was compile-time. Even with low optimization the compiler will generate the same code, and it's much less clumsy and arguably cleaner to read than the class version.

回答2:

You can throw from the expression(s) that initialize t0 or t1, or any constructor that takes at least one argument.

class C {
  T0 t0; // can be either valid or invalid, but does not throw directly
  T1 t1; // heavy object, do not construct if t0 is invalid, by throwing before
  C(int n) // try one of these alternatives:
    : t0( n_valid( n )? n : throw my_exc() ), // sanity pre-check
OR    t1( t0.check()? throw my_exc() : 0 ), // add dummy argument to t1::t1()
OR    t1( t0.check()? throw my_exc() : t1() ) // throw or invoke copy/move ctor
      {}
};

Note that a throw expression has void type, making throw more like an operator than a statement. The ?: operator has a special case to prevent that void from interfering with its type deduction.

回答3:

This is a way to throw from the initializer list

C(int n)
    : t0(n > 0 ? n : throw std::runtime_error("barf")),
      t1() {}

You're saying "throw exception if t0(n) is not valid". Why don't you throw from the constructor of T0?

An object is supposed to be valid after construction.

回答4:

Just wrap class T0 inside another class which does throw in cases like this:

class ThrowingT0
{
    T0 t0;
public:
    explicit ThrowingT0(int n) : t0(n) {
        if (t0.SomeFailureMode())
            throw std::runtime_error("WTF happened.");
    };
    const T0& GetReference() const {
        return t0;
    };
    T0& GetReference() {
        return t0;
    };
};

class C
{
    ThrowingT0 t0;
    T1 t1;
public:
    explicit C(int n) : t0(n), t1() {
    };
    void SomeMemberFunctionUsingT0() {
        t0.GetReference().SomeMemberFunction();
    };
};

来源：https://stackoverflow.com/questions/2672398/throw-exception-from-constructor-initializer

标签

c++

exception

ctor-initializer