思路:
找最大最小值、求和. 没有什么特别的地方.
#include <iostream>
using namespace std;
int main()
{
ios::sync_with_stdio(false);
cin.tie(0);
int n;
cin >> n;
int maxn = -10001, minn = 10001, sum = 0;
for (int i = 0; i < n; i++) {
int x;
cin >> x;
maxn = max(x, maxn);
minn = min(x, minn);
sum += x;
}
cout << maxn << '\n' << minn << '\n' << sum << endl;
return 0;
}
来源:https://www.cnblogs.com/AntonLiu/p/12247043.html