问题
I want to configure jackson to output any date/time values with the following format:
spring.jackson.date-format=yyyy-MM-dd'T'HH:mm:ss
I'm fetching many database rows and return them just as a json map.
@RestController
public class MyService {
@GetMapping
public List<Map<String, Object>> get(Param params) {
return jdbcTemplate.queryForList(sql, params);
}
}
Problem: the databases and jvm default timezone is Europe/Berlin, thus UTC+2. Therefor jackson automatically converts any database-received java.sql.Timestamp to UTC first (subtracts 2 hours), and then outputs them via json.
In the mysql database itself, it's a datetime type.
But I just want jackson to output the timestamps "as is", without prior conversion! Is that possible to skip timezone correction?
I just want to ignore the timezone without conversation. Just cut it.
回答1:
Approach #1: Setting a default time zone
You could set a time zone in the date format used by ObjectMapper. It will be used for Date and subclasses:
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("Europe/Berlin"));
ObjectMapper mapper = new ObjectMapper();
mapper.setDateFormat(dateFormat);
In Spring applications, to configure ObjectMapper, you can do as follows:
@Bean
public ObjectMapper objectMapper() {
DateFormat dateFormat = new SimpleDateFormat("yyyy-MM-dd'T'HH:mm:ss");
dateFormat.setTimeZone(TimeZone.getTimeZone("Europe/Berlin"));
ObjectMapper mapper = new ObjectMapper();
mapper.setDateFormat(dateFormat);
return mapper;
}
In Spring Boot you can use the property spring.jackson.time-zone to define the timezone:
spring.jackson.time-zone: Europe/Berlin
For more details on the common application properties, refer to the documentation.
Approach #2: Using the Java 8 Date and Time API
Instead of using Timestamp, you could consider LocaDateTime from the JSR-310. It was introduced in Java 8. The "local" date and time classes (LocalDateTime, LocalDate and LocalTime) are not tied to any one locality or time zone. From the LocalDateTime documentation:
This class does not store or represent a time-zone. Instead, it is a description of the date, as used for birthdays, combined with the local time as seen on a wall clock. It cannot represent an instant on the time-line without additional information such as an offset or time-zone.
This answer will give you more details on the new date and time classes.
Jackson has a module that supports JSR-310 types. Add it to your dependencies:
<dependency>
<groupId>com.fasterxml.jackson.datatype</groupId>
<artifactId>jackson-datatype-jsr310</artifactId>
<version>2.9</version>
</dependency>
Then register the JavaTimeModule module in your ObjectMapper instance:
ObjectMapper mapper = new ObjectMapper();
mapper.registerModule(new JavaTimeModule());
mapper.disable(SerializationFeature.WRITE_DATES_AS_TIMESTAMPS);
Most JSR-310 types will be serialized using a standard ISO-8601 string representation. If you need a custom format, you can use your own serializer and deserializer implementation. See the documentation for details.
回答2:
Finally it turned out the simples way is to just set the jacksons ObjectMapper (which uses UTC by defaut) timezone to the jvm defaults:
@Bean
public Jackson2ObjectMapperBuilderCustomizer init() {
return new Jackson2ObjectMapperBuilderCustomizer() {
@Override
public void customize(Jackson2ObjectMapperBuilder builder) {
builder.timeZone(TimeZone.getDefault());
}
};
}
I'd appreciate if anybody knows how I can achieve the same by just using the spring.jackson.time-zone application.property.
来源:https://stackoverflow.com/questions/50045912/how-to-skip-jackson-timezone-correction-in-spring-mvc