I want to display the file Name in the log statement

问题

For every logger statement with any level, I need to display the file name from where the log statement executed, below is the illustration I given below:

Example : Below is the line executed from JobWork.js

logger.info("getInCompleteJobs in job works");

Actual :

2012-11-05T06:07:19.158Z - info: getInCompleteJobs in job works

Required :

2012-11-05T06:07:19.158Z - info JobWork.js : getInCompleteJobs in job works

Without passing the fileName as a parameter from the log statement it should give the filename.

回答1:

You can use the stack trace information attached to v8's Error object to find out what file/line your code was called from. This approach works well, but it does not perform well; so if you use it during development, you will want to disable it when you go to production.

So you could do something like this:

  var logger_info_old = logger.info;
  logger.info = function(msg) {
    var fileAndLine = traceCaller(1);
    return logger_info_old.call(this, fileAndLine + ":" + msg);
  }

  /**
  * examines the call stack and returns a string indicating 
  * the file and line number of the n'th previous ancestor call.
  * this works in chrome, and should work in nodejs as well.  
  *
  * @param n : int (default: n=1) - the number of calls to trace up the
  *   stack from the current call.  `n=0` gives you your current file/line.
  *  `n=1` gives the file/line that called you.
  */
  function traceCaller(n) {
    if( isNaN(n) || n<0) n=1;
    n+=1;
    var s = (new Error()).stack
      , a=s.indexOf('\n',5);
    while(n--) {
      a=s.indexOf('\n',a+1);
      if( a<0 ) { a=s.lastIndexOf('\n',s.length); break;}
    }
    b=s.indexOf('\n',a+1); if( b<0 ) b=s.length;
    a=Math.max(s.lastIndexOf(' ',b), s.lastIndexOf('/',b));
    b=s.lastIndexOf(':',b);
    s=s.substring(a+1,b);
    return s;
  }

回答2:

Looks like you're using Winston here - I typically pass module into my logger module and then set Winston's label property to a parsed version of module.filename. Something like:

logger.js:

const path = require('path');

// Return the last folder name in the path and the calling
// module's filename.
const getLabel = function(callingModule) {
  const parts = callingModule.filename.split(path.sep);
  return path.join(parts[parts.length - 2], parts.pop());
};

module.exports = function (callingModule) {
  return new winston.Logger({
    transports: [new winston.transports.Console({
      label: getLabel(callingModule)
    })]
  });
};

Usage (assume module is controllers/users.js):

const logger = require('./logger')(module);
logger.info('foo');

Result:

2014-11-25T15:31:12.186Z - info: [controllers/users.js] foo

回答3:

Assuming each file is a separate node process, you could use something like process.argv[1].match(/[\w-]+\.js/gi)[0]

If you are looking for something that will work in modules this might work:

process.mainModule.filename.match(/[\w-]+\.js/gi)[0]

回答4:

Use this code and it will give you the log with the filename and line number. Paste this code in a new file winston.js and this requires this file to use it.

var winston = require('winston')
var path = require('path')
var PROJECT_ROOT = path.join(__dirname, '..')
var appRoot = require('app-root-path');


const options = {
  file: {
    level: 'info',
    filename: `${appRoot}/logs/app.log`,
    handleExceptions: true,
    json: true,
    maxsize: 5242880, // 5MB
    maxFiles: 5,
    colorize: false,
    timestamp: true
  },
  console: {
    level: 'debug',
    handleExceptions: true,
    json: true,
    colorize: true,
    timestamp: true
  }
};

var logger = new winston.Logger({
  transports: [
    new winston.transports.File(options.file),
    new winston.transports.Console(options.console)
  ],
  exitOnError: false // do not exit on handled exceptions
});

logger.stream = {
  write: function (message) {
    logger.info(message)
  }
}

// A custom logger interface that wraps winston, making it easy to instrument
// code and still possible to replace winston in the future.

module.exports.debug = module.exports.log = function () {
  logger.debug.apply(logger, formatLogArguments(arguments))
}

module.exports.info = function () {
  logger.info.apply(logger, formatLogArguments(arguments))
}

module.exports.warn = function () {
  logger.warn.apply(logger, formatLogArguments(arguments))
}

module.exports.error = function () {
  logger.error.apply(logger, formatLogArguments(arguments))
}

module.exports.stream = logger.stream

/**
 * Attempts to add file and line number info to the given log arguments.
 */
function formatLogArguments (args) {
  args = Array.prototype.slice.call(args)

  var stackInfo = getStackInfo(1)

  if (stackInfo) {
    // get file path relative to project root
    var calleeStr = '(' + stackInfo.relativePath + ':' + stackInfo.line + ')'

    if (typeof (args[0]) === 'string') {
      args[0] = calleeStr + ' ' + args[0]
    } else {
      args.unshift(calleeStr)
    }
  }

  return args
}

/**
 * Parses and returns info about the call stack at the given index.
 */
function getStackInfo (stackIndex) {
  // get call stack, and analyze it
  // get all file, method, and line numbers
  var stacklist = (new Error()).stack.split('\n').slice(3)

  // stack trace format:
  // http://code.google.com/p/v8/wiki/JavaScriptStackTraceApi
  // do not remove the regex expresses to outside of this method (due to a BUG in node.js)
  var stackReg = /at\s+(.*)\s+\((.*):(\d*):(\d*)\)/gi
  var stackReg2 = /at\s+()(.*):(\d*):(\d*)/gi

  var s = stacklist[stackIndex] || stacklist[0]
  var sp = stackReg.exec(s) || stackReg2.exec(s)

  if (sp && sp.length === 5) {
    return {
      method: sp[1],
      relativePath: path.relative(PROJECT_ROOT, sp[2]),
      line: sp[3],
      pos: sp[4],
      file: path.basename(sp[2]),
      stack: stacklist.join('\n')
    }
  }
}

来源：https://stackoverflow.com/questions/13410754/i-want-to-display-the-file-name-in-the-log-statement

标签

node.js

logging

winston