Given a binary search tree and a node in it, find the in-order successor of that node in the BST.
The successor of a node p is the node with the smallest key greater than p.val.
Example 1:
Input: root = [2,1,3], p = 1 Output: 2 Explanation: 1's in-order successor node is 2. Note that both p and the return value is of TreeNode type.
/**
* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
class Solution {
public TreeNode inorderSuccessor(TreeNode root, TreeNode p) {
TreeNode res = null;
while (root != null) {
if (root.val <= p.val) {
root = root.right;
} else {
// only when p.val < root, root can possibly be the successor, continue check root.left
res = root;
root = root.left;
}
}
return res;
}
}
Good Reference: https://leetcode.com/problems/inorder-successor-in-bst/discuss/72653/Share-my-Java-recursive-solution
来源:https://www.cnblogs.com/xuanlu/p/12242399.html