Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
- The number of elements initialized in nums1 and nums2 are m and n respectively.
- You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2.
Example:
Input: nums1 = [1,2,3,0,0,0], m = 3 nums2 = [2,5,6], n = 3 Output: [1,2,2,3,5,6]
/**
* @param {number[]} nums1
* @param {number} m
* @param {number[]} nums2
* @param {number} n
* @return {void} Do not return anything, modify nums1 in-place instead.
*/
var merge = function(nums1, m, nums2, n) {
while (m > 0 && n > 0) {
const n2 = nums2[n - 1];
const n1 = nums1[m - 1];
let toSave;
if (n2 > n1) {
nums1[m + n - 1] = n2;
n = n - 1;
} else {
nums1[m + n - 1] = n1;
m = m - 1;
}
}
if (n > 0 && m === 0) {
while (n > 0) {
const n2 = nums2[n - 1];
nums1[n - 1] = n2;
n--;
}
}
};
来源:https://www.cnblogs.com/Answer1215/p/12242044.html