Left shift Float type

只谈情不闲聊 提交于 2020-01-29 08:01:25

问题


get a complier error while trying to do

float_val=float_val<<1;

It gives out a error saying "error C2296: '<<' : illegal, left operand has type 'float '"

Can't v left shift float vars? Why is this so?


回答1:


You can't left shift float variables, because (a) your FPU generally will not have a barrel shifter exposed to you so physically cannot generate code to do that, and (b) what would it even mean? The underlying bit representation consists of multiple fields with different meanings, do you really want those bits bleeding into each other?

If you want to multiply the number held in that variable by two, you should just do that instead.

If you want to reinterpret the float as some type that left shift makes sense on (e.g. a suitably large unsigned integer type) for some horrible bit hack like Carmack's square root, well, you can do that too, but on modern hardware it is highly unlikely that you really need to: seriously consider if there is a better way to do what you want.




回答2:


Check out the standard function ldexpf if you want to quickly multiply or divide a float by a power of 2. A bit obscure obviously :-).

https://linux.die.net/man/3/ldexpf




回答3:


Floating point numbers don't have bits at the level of value-representation, which is why you can't apply bitwise operations to them.

See this answer for more information.




回答4:


Shifting floats makes no sense since it's represented as the concatenation of a sign bit, an exponent and a mantissa. Since shifting operation is about shifting bits, it would imply shifting bits from mantissa to exponent and / or to sign bit.




回答5:


Since the left shift operator is defined as multiplication by a power of 2, it makes perfect sense for floating point types. However, the C language does not define its use, so instead you have to use the scalbn function or similar.




回答6:


You cannot left shift objects of float type.

C says the operands of the bitwise shift operators shall have integer type.




回答7:


You'd have to transform the float to something else first. Such as:

float f = 128;
f = (float) (((int) f) << 1 );

And in the above, f should be 256.0.

Now obviously this is problematic if you start with 128.4 as the cast will drop the .4. You may not want to be using a float in first place.



来源:https://stackoverflow.com/questions/9315539/left-shift-float-type

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!