问题
I have a table that includes the following column:
 mytable <- data.frame(beta_0 = c(1,2,3)
What I want to do is output a table with a column header in latex markup, e.g. $\beta_0$
However, I can not seem to figure out how to output the "$\beta_0$" using print.xtable:
colnames(mytable) <- "$\beta_0$"
library(xtable)
print(xtable(mytable), include.rownames = F)
returns a column header of
\eta\_0\$
instead of
$\beta_0$
I presume that the answer is the "sanitize.colnames.function" argument to print.xtable, but it is not obvious to me how to use this, and ?print.xtable provides no examples.
Specifically, I would like to output a latex table like:
\begin{table}[ht]
 \begin{center}
  \begin{tabular}{r}
    \hline
    $\beta_0$ \\ 
    \hline
    1.00 \\ 
    2.00 \\ 
    3.00 \\ 
    \hline
  \end{tabular}
 \end{center}
\end{table}
回答1:
Two issues here; first, you need a double backslash as otherwise it treats it as a control sequence.  Second, by default, xtable sanitizes text so that it won't break LaTeX.  Use one of the sanitize. parameters to control this; to do no sanitizing, pass it the identity function.
colnames(mytable) <- "$\\beta_0$"
print(xtable(mytable), include.rownames = F, sanitize.colnames.function = identity)
来源:https://stackoverflow.com/questions/8732712/handling-latex-backslashes-in-xtable