In Go, how do I capture stdout of a function into a string?

问题

In Python, for example, I can do the following:

realout = sys.stdout
sys.stdout = StringIO.StringIO()
some_function() # prints to stdout get captured in the StringIO object
result = sys.stdout.getvalue()
sys.stdout = realout

Can you do this in Go?

回答1:

I agree you should use the fmt.Fprint functions if you can manage it. However, if you don't control the code whose output you're capturing, you may not have that option.

Mostafa's answer works, but if you want to do it without a temporary file you can use os.Pipe. Here's an example that's equivalent to Mostafa's with some code inspired by Go's testing package.

package main

import (
    "bytes"
    "fmt"
    "io"
    "os"
)

func print() {
    fmt.Println("output")
}

func main() {
    old := os.Stdout // keep backup of the real stdout
    r, w, _ := os.Pipe()
    os.Stdout = w

    print()

    outC := make(chan string)
    // copy the output in a separate goroutine so printing can't block indefinitely
    go func() {
        var buf bytes.Buffer
        io.Copy(&buf, r)
        outC <- buf.String()
    }()

    // back to normal state
    w.Close()
    os.Stdout = old // restoring the real stdout
    out := <-outC

    // reading our temp stdout
    fmt.Println("previous output:")
    fmt.Print(out)
}

回答2:

This answer is similar to the previous ones but looks cleaner by using io/ioutil.

http://play.golang.org/p/fXpK0ZhXXf

package main

import (
  "fmt"
  "io/ioutil"
  "os"
)

func main() {
  rescueStdout := os.Stdout
  r, w, _ := os.Pipe()
  os.Stdout = w

  fmt.Println("Hello, playground") // this gets captured

  w.Close()
  out, _ := ioutil.ReadAll(r)
  os.Stdout = rescueStdout

  fmt.Printf("Captured: %s", out) // prints: Captured: Hello, playground
}

回答3:

I don't recommend this, but you can achieve it with altering os.Stdout. Since this variable is of type os.File, your temporary output should also be a file.

package main

import (
    "fmt"
    "io/ioutil"
    "os"
    "path/filepath"
)

func print() {
    fmt.Println("output")
}

func main() {
    // setting stdout to a file
    fname := filepath.Join(os.TempDir(), "stdout")
    fmt.Println("stdout is now set to", fname)
    old := os.Stdout // keep backup of the real stdout
    temp, _ := os.Create(fname) // create temp file
    os.Stdout = temp

    print()

    // back to normal state
    temp.Close()
    os.Stdout = old // restoring the real stdout

    // reading our temp stdout
    fmt.Println("previous output:")
    out, _ := ioutil.ReadFile(fname)
    fmt.Print(string(out))
}

I don't recommend because this is too much hacking, and not very idiomatic in Go. I suggest passing an io.Writer to the functions and writing outputs to that. This is the better way to do almost the same thing.

package main

import (
    "bytes"
    "fmt"
    "io"
    "os"
)

func print(w io.Writer) {
    fmt.Fprintln(w, "output")
}

func main() {
    fmt.Println("print with byes.Buffer:")
    var b bytes.Buffer
    print(&b)
    fmt.Print(b.String())

    fmt.Println("print with os.Stdout:")
    print(os.Stdout)
}

回答4:

I think the whole idea is not advisable (race condition) at all, but I guess one can mess with os.Stdout in a way similar/analogical to your example.

来源：https://stackoverflow.com/questions/10473800/in-go-how-do-i-capture-stdout-of-a-function-into-a-string

标签

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