问题
This is a follow-up of this question: Rewrite URL - how to get the hostname and the path?
I got this Rewrite Rule:
RewriteEngine On
RewriteRule ^(http://[-A-Za-z0-9+&@#/%=~_|!:,.;]*)/([-A-Za-z0-9+&@#/%=~_|!:,.;]*)\?([A-Za-z0-9+&@#/%=~_|!:,.;]*)$ http://http://www.xmldomain.com/bla/$2?$3&rtype=xslt&xsl=$1/$2.xsl
it seems to be correct, and exactly what I need. But it doesn't work on my server. I get a 404 page not found error.
mod_rewrite is enabled, as the following simple rule is working fine:
RewriteEngine On
RewriteRule ^page/([^/\.]+)/?$ index.php?page=$1 [L]
Can you help?
Thanks
回答1:
maybe try this
RewriteRule ^/(.+)/page/([^/]+)/(.*)$ domain/index.php?page=$2&host=%{HTTP_HOST} [QSA,NC,L]
回答2:
It believe it's not correct. You cannot use a url as the first operand of RewriteRule.
What you should write instead of
RewriteRule ^(http://[-A-Za-z0-9+&@#/%=~_|!:,.;]*)/([-A-Za-z0-9+&@#/%=~_|!:,.;]*)\?([A-Za-z0-9+&@#/%=~_|!:,.;]*)$ http://http://www.xmldomain.com/bla/$2?$3&rtype=xslt&xsl=$1/$2.xsl
is (edit: for some reason you want to match the last portion path, I'll oblige)
RewriteCond %{HTTP_HOST} !=""
RewriteRule ^/(.*?)([^/]+)(?:/)?$ http://www.xmldomain.com/bla/page?rtype=xslt&xsl=http%3A%2F%2F%{HTTP_HOST}%2F$1$2.xsl%2A [QSA,B,P,NE]
Also note that rewrite rules are not automatically inherited by virtual hosts. You must activate inheritance explicitly.
来源：https://stackoverflow.com/questions/2880996/mod-rewrite-rewriterule-is-not-working