While fetching all links,Ignore logout link from the loop and continue navigation in selenium java

问题

I am fetching all the links in the page and navigating to all links. In that one of the link is Logout. How do i skip/ignore Logout link from the loop?

I want to skip Logout link and proceed

List demovar=driver.findElements(By.tagName("a")); System.out.println(demovar.size());

   ArrayList<String> hrefs = new ArrayList<String>(); //List for storing all href values for 'a' tag

      for (WebElement var : demovar) {
          System.out.println(var.getText()); // used to get text present between the anchor tags
          System.out.println(var.getAttribute("href"));
          hrefs.add(var.getAttribute("href")); 
          System.out.println("*************************************");
      }

      int logoutlinkIndex = 0;

      for (WebElement linkElement : demovar) {
               if (linkElement.getText().equals("Log Out")) {
                           logoutlinkIndex = demovar.indexOf(linkElement);
                           break;
                }

      }

      demovar.remove(logoutlinkIndex);

      //Navigating to each link
      int i=0;
      for (String href : hrefs) {
          driver.navigate().to(href);
          System.out.println((++i)+": navigated to URL with href: "+href);
          Thread.sleep(5000); // To check if the navigation is happening properly.
          System.out.println("+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++");

回答1:

If you want to leave out the Logout link from the loop instead of creating the List as driver.findElements(By.tagName("a")); as an alternative you can use:

driver.findElements(By.xpath("//a[not(contains(.,'Log Out'))]"));

Reference

You can find a couple of relevant discussions in:

How to locate the button element using Selenium through Python
What does contains(., 'some text') refers to within xpath used in Selenium
How does dot(.) in xpath to take multiple form in identifying an element and matching a text

回答2:

Java approach to remove "not interesting" link using Stream.filter() function:

List<String> hrefs = driver.findElements(By.className("a"))
        .stream()
        .filter(link -> link.getText().equals("Log out"))
        .map(link -> link.getAttribute("href"))
        .collect(Collectors.toList());

Using XPath != operator solution to collect only links which text is not equal to Log Out:

List<String> hrefs = driver.findElements(By.xpath("//a[text() != 'Log out']"))
        .stream()
        .map(link -> link.getAttribute("href"))
        .collect(Collectors.toList());

来源：https://stackoverflow.com/questions/57293901/while-fetching-all-links-ignore-logout-link-from-the-loop-and-continue-navigatio

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