return value after a promise [duplicate]

风流意气都作罢 提交于 2019-11-26 03:39:02

问题


I have a javascript function where I want to return the value that I get after the return method. Easier to see than explain

function getValue(file){
    var val;
    lookupValue(file).then(function(res){
       val = res.val;
    }
    return val;
}

What is the best way to do this with a promise. As I understand it, the return val will return before the lookupValue has done it\'s then, but the I can\'t return res.val as that is only returning from the inner function.


回答1:


Use a pattern along these lines:

function getValue(file) {
  return lookupValue(file);
}

getValue('myFile.txt').then(function(res) {
  // do whatever with res here
});

(although this is a bit redundant, I'm sure your actual code is more complicated)




回答2:


The best way to do this would be to use the promise returning function as it is, like this

lookupValue(file).then(function(res) {
    // Write the code which depends on the `res.val`, here
});

The function which invokes an asynchronous function cannot wait till the async function returns a value. Because, it just invokes the async function and executes the rest of the code in it. So, when an async function returns a value, it will not be received by the same function which invoked it.

So, the general idea is to write the code which depends on the return value of an async function, in the async function itself.



来源:https://stackoverflow.com/questions/22951208/return-value-after-a-promise

易学教程内所有资源均来自网络或用户发布的内容,如有违反法律规定的内容欢迎反馈
该文章没有解决你所遇到的问题?点击提问,说说你的问题,让更多的人一起探讨吧!