问题
I am using GDB on a x64 CPU. As you can see, I am trying to access the value of the rip register and for some reason the address of the instruction the register is pointing to is displayed using 5s instead of 0s as it should be.
Dump of assembler code for function main:
0x0000000000001139 <+0>: push rbp
0x000000000000113a <+1>: mov rbp,rsp
0x000000000000113d <+4>: sub rsp,0x10
0x0000000000001141 <+8>: mov DWORD PTR [rbp-0x4],0x0
0x0000000000001148 <+15>: mov DWORD PTR [rbp-0x4],0x0
0x000000000000114f <+22>: jmp 0x1161 <main+40>
0x0000000000001151 <+24>: lea rdi,[rip+0xeac] # 0x2004
0x0000000000001158 <+31>: call 0x1030 <puts@plt>
0x000000000000115d <+36>: add DWORD PTR [rbp-0x4],0x1
0x0000000000001161 <+40>: cmp DWORD PTR [rbp-0x4],0x9
0x0000000000001165 <+44>: jle 0x1151 <main+24>
0x0000000000001167 <+46>: mov eax,0x0
0x000000000000116c <+51>: leave
0x000000000000116d <+52>: ret
End of assembler dump.
(gdb) break main
Breakpoint 1 at 0x1141: file Desktop/myprogram.c, line 6.
(gdb) run
Starting program: /home/william/Desktop/a.out
Breakpoint 1, main () at Desktop/myprogram.c:6
6 int i = 0;
(gdb) info register rip
rip 0x555555555141 0x555555555141 <main+8>
As you can see, the rip register contains the address of the mov instruction listed above but for some reason has replaced all the 0s for 5s. Any idea why?
回答1:
Before running a position-independent executable, there is no base address so gcc assumes 0. This matches what you'll see from objdump -drwC -Mintel /bin/ls or whatever.
On running the executable to create a process, the OS's program-loader maps it to an address. x86-64 Linux chooses a page address that starts with 0x0000555555555... when GDB disables ASLR.
If you run it outside GDB, or with set disable-randomization off, then the address will still start with 0x000055555, but be randomized in some range.
来源：https://stackoverflow.com/questions/51791746/why-is-gdb-filling-the-0s-of-a-memory-address-with-5s-during-a-register-info