Center of rotated cv::Rect

问题

I have an image, and I place a rectangle on the image. Then I rotate the image. How do I get the center of the rectangle on the rotated image?

Or can I rotate a rectangle somehow to put on rotated image? I think in this case rotation must be done along same point with point used to rotate image.

This is the image with a rectangle placed on it.

This is the rotated image.

Here is the code I use to rotate my image:

cv::Mat frame, frameRotated;
frame = cv::imread("lena.png");

cv::Rect rect(225,250,150,150);
cv::rectangle(frame, rect, cv::Scalar(0,0,255),2);

int theta = 30;
double radians = theta * PI / 180.0;            

double sin = abs(std::sin(radians));
double cos = abs(std::cos(radians));

int newWidth = (int) (frame.cols * cos + frame.rows * sin);
int newHeight = (int) (frame.cols * sin + frame.rows * cos);

cv::Mat targetMat(cv::Size(newWidth, newHeight), frame.type());

int offsetX = (newWidth - frame.cols) / 2;
int offsetY = (newHeight - frame.rows) / 2;

frame.copyTo(targetMat.rowRange(offsetY, offsetY + frame.rows).colRange(offsetX, offsetX + frame.cols));

cv::Point2f src_center(targetMat.cols/2.0F, targetMat.rows/2.0F);
cv::Mat rot_mat = cv::getRotationMatrix2D(src_center, theta, 1.0);
cv::warpAffine(targetMat, frameRotated, rot_mat, targetMat.size());

imshow("frame", frame); 
imshow("rotated frame", frameRotated);

EDIT

Suppose I have a point in the rotated image, how do I get corresponding point in the original image using rotation matrix?

回答1:

You only need to use rot_mat to transform the original center of the rect. I tested the below and it works:

cv::Rect r(250, 350, 20, 30);
cv::Point2d c(r.x + r.width / 2, r.y + r.height / 2);
// c is center of rect

// get c's location in targetMat when frame is copied
c.x += offsetX;  
c.y += offsetY;


int theta = 30;
double radians = theta * M_PI / 180.0;            

cv::Point2d src_center(targetMat.cols/2.0F, targetMat.rows/2.0F);
cv::Mat rot_mat = cv::getRotationMatrix2D(src_center, theta, 1.0);

// now transform point using rot_mat
double *x = rot_mat.ptr<double>(0);
double *y = rot_mat.ptr<double>(1);
Point2d dst(x[0] * c.x + x[1] * c.y + x[2], 
            y[0] * c.x + y[1] * c.y + y[2]);
// dst is center of transformed rect

EDIT

To transform a point from the rotated image you just need to reverse the process:

// undo translation
Point2d dst1(dst.x - x[2], dst.y - y[2]); 

// undo rotation
Point2d dst2(x[0] * dst1.x - x[1] * dst1.y, -y[0] * dst1.x + y[1] * dst1.y); 

// undo shift
Point2d in_unrotated_image(dst2.x - offsetX, dst2.y - offsetY);

回答2:

You can translate any point in your source Mat to rotated Mat by multiplying with the Rotation matrix.

If you need to translate X,Y and given T=1, you can do this by Mat multiplication

 |  cosθ  sinθ  Tx |   | X |    | _X |
 |                 | * | Y |  = |    |
 | -sinθ  cosθ  Ty |   | 1 |    | _Y |

where Tx and Ty is the translation along the x and y see OpenCV Doc.

Suppose you need to find the centre (cent_x,cent_y) of source Mat in rotated Mat

Mat rot_mat = getRotationMatrix2D(src_center, theta, 1.0); //Find the rotation matrix 
Mat co_Ordinate = (Mat_<double>(3,1) << cent_x,cent_y,1); //Create 3x1 matrix with input co-ordinates.

Mat rst=rot_mat*co_Ordinate; // Multiply rotation matrix with input co-ordinate matrix
trans_x=(int)rst.at<double>(0,0); //First row of result will be x
trans_y=(int)rst.at<double>(1,0); //Second row of result will be y.

Hopes these helpful....

回答3:

I've solved the problem in second question.

I used the same code provided in the accepted answer and create rotation matrix with minus theta.

来源：https://stackoverflow.com/questions/19786333/center-of-rotated-cvrect

标签

OpenCV

rotation

rectangles