问题
Is there any way to use boto3 to loop the bucket contents in two different buckets (source and target) and if it finds any key in source that does not match with target, it uploads it to the target bucket. please note I do not want to use aws s3 sync. I am currently using the following code for doing this job:
import boto3
s3 = boto3.resource('s3')
src = s3.Bucket('sourcenabcap')
dst = s3.Bucket('destinationnabcap')
objs = list(dst.objects.all())
for k in src.objects.all():
if (k.key !=objs[0].key):
# copy the k.key to target
回答1:
If you only wish to compare by Key (ignoring differences within objects), you could use something like:
s3 = boto3.resource('s3')
source_bucket = s3.Bucket('source')
destination_bucket = s3.Bucket('destination')
destination_keys = [object.key for object in destination_bucket.objects.all()]
for object in source_bucket.objects.all():
if (object.key not in destination_keys):
# copy object.key to destination
回答2:
in case you decide not to use boto3. the sync command is still not available for boto3, so you could use it directly
# python 3
import os
sync_command = f"aws s3 sync s3://source-bucket/ s3://destination-bucket/"
os.system(sync_command)
回答3:
I've just implemented a simple class for this matter (sync a local folder to a bucket). I'm posting it here hoping it help anyone with the same issue.
You could modify S3Sync.sync in order to take file size into account.
class S3Sync:
"""
Class that holds the operations needed for synchronize local dirs to a given bucket.
"""
def __init__(self):
self._s3 = boto3.client('s3')
def sync(self, source: str, dest: str) -> [str]:
"""
Sync source to dest, this means that all elements existing in
source that not exists in dest will be copied to dest.
No element will be deleted.
:param source: Source folder.
:param dest: Destination folder.
:return: None
"""
paths = self.list_source_objects(source_folder=source)
objects = self.list_bucket_objects(dest)
# Getting the keys and ordering to perform binary search
# each time we want to check if any paths is already there.
object_keys = [obj['Key'] for obj in objects]
object_keys.sort()
object_keys_length = len(object_keys)
for path in paths:
# Binary search.
index = bisect_left(object_keys, path)
if index == object_keys_length:
# If path not found in object_keys, it has to be sync-ed.
self._s3.upload_file(str(Path(source).joinpath(path)), Bucket=dest, Key=path)
def list_bucket_objects(self, bucket: str) -> [dict]:
"""
List all objects for the given bucket.
:param bucket: Bucket name.
:return: A [dict] containing the elements in the bucket.
Example of a single object.
{
'Key': 'example/example.txt',
'LastModified': datetime.datetime(2019, 7, 4, 13, 50, 34, 893000, tzinfo=tzutc()),
'ETag': '"b11564415be7f58435013b414a59ae5c"',
'Size': 115280,
'StorageClass': 'STANDARD',
'Owner': {
'DisplayName': 'webfile',
'ID': '75aa57f09aa0c8caeab4f8c24e99d10f8e7faeebf76c078efc7c6caea54ba06a'
}
}
"""
try:
contents = self._s3.list_objects(Bucket=bucket)['Contents']
except KeyError:
# No Contents Key, empty bucket.
return []
else:
return contents
@staticmethod
def list_source_objects(source_folder: str) -> [str]:
"""
:param source_folder: Root folder for resources you want to list.
:return: A [str] containing relative names of the files.
Example:
/tmp
- example
- file_1.txt
- some_folder
- file_2.txt
>>> sync.list_source_objects("/tmp/example")
['file_1.txt', 'some_folder/file_2.txt']
"""
path = Path(source_folder)
paths = []
for file_path in path.rglob("*"):
if file_path.is_dir():
continue
str_file_path = str(file_path)
str_file_path = str_file_path.replace(f'{str(path)}/', "")
paths.append(str_file_path)
return paths
if __name__ == '__main__':
sync = S3Sync()
sync.sync("/temp/some_folder", "some_bucket_name")
来源:https://stackoverflow.com/questions/53517519/sync-two-buckets-through-boto3