Celery Exception Handling

问题

Suppose i have this task definition:

def some_other_foo(input)
raise Exception('This is not handled!')
return input

@app.task(
  bind=True,
  max_retries=5,
  soft_time_limit=20)
def some_foo(self, someInput={}):
   response=""
   try:
     response = some_other_foo(someInput)
   except Exception as exc:
     self.retry(countdown=5, exc=exc)
     response="error"
 return response

I have a problem that exception is not handled in some_foo, I get error instead of response="error", task is crashed and i get Traceback that indicates an Exception was raised.

Is it possible to return regular response, but to set celery task as failed, so result in flower will be failed ?

I am using:
Celery 4.1
AMPQ as broker
Celery Flower as monitoring

回答1:

Try \ except works fine. Your task will always be unsuccessful because you called self.retry before return. Let's make a little test:

from celery import Celery

app = Celery(name_app,broker_settings_etc....)

def some_other_foo(value):
    raise Exception('This is not handled!')

@app.task(
  bind=True,
  max_retries=5,
  soft_time_limit=20)
def some_foo(self):
    response = ""

    try:
        response = some_other_foo('test')
    except Exception as exc:
        self.retry(countdown=5, exc=exc)
        response = "error"

    return response

Run celery app and call our task. You will see in celery logs something like this:

3fb-81de-e4149fa88f4c] retry: Retry in 5s: Exception('This is not handled!',)
[2017-08-18 15:50:34,160: INFO/MainProcess] Received task: tasks.some_foo[b656731b-c85d-43fb-81de-e4149fa88f4c] eta:[2017-08-18 12:50:39.156912+00:00]
[2017-08-18 15:50:34,161: INFO/MainProcess] Task tasks.some_foo[b656731b-c85d-43fb-81de-e4149fa88f4c] retry: Retry in 5s: Exception('This is not handled!',)
[2017-08-18 15:50:39,511: ERROR/MainProcess] Task tasks.some_foo[b656731b-c85d-43fb-81de-e4149fa88f4c] raised unexpected: Exception('This is not handled!',)
Traceback (most recent call last): 
# trace here...
Exception: This is not handled!

How it works. You set for the task max_retries=5. When you called self.retry(countdown=5, exc=exc) Celery interrupts processing of task and try to restart task with countdown(in our case = 5). After 5 attempts(max_retries) Celery won't rerun task.

Now, let's change our try \ except block to:

try:
    response = some_other_foo('test')
except Exception:
    print 'handled'
    response = "bad response"

Restart Celery and run our task. Let's check log:

[2017-08-18 15:58:41,893: INFO/MainProcess] Received task: tasks.some_foo[1437e7ce-1c69-4042-824b-5602f486c025]
[2017-08-18 15:58:41,895: WARNING/Worker-3] handled
[2017-08-18 15:58:41,896: INFO/MainProcess] Task tasks.some_foo[1437e7ce-1c69-4042-824b-5602f486c025] succeeded in 0.00186271299026s: 'bad response'

As you can see handler works fine.

So, summarize. If you call self.retry, Celery will interrupt processing of task and try to restart a current task.

来源：https://stackoverflow.com/questions/45611122/celery-exception-handling

标签

python

python-2.7

celery

celeryd