问题
For example, one column in my table is an array, I want to check if that column contains an element that contains substring "denied" (so elements like "denied at 12:00 pm", "denied by admin" will all count, I believe I will have to use "like" to identify the pattern). How to write sql for this?
回答1:
Use presto's array functions:
filter()
, which returns elements that satisfy the given conditioncardinality()
, which returns the size of an array:
Like this:
where cardinality(filter(myArray, x -> x like '%denied%')) > 0
回答2:
See array operator docs here
contains(array_column,'denied')
来源:https://stackoverflow.com/questions/50766928/presto-array-contains-an-element-that-likes-some-pattern