问题
I've got an Image Uri, retrieved using the following:
public Uri getImageUri(Context inContext, Bitmap inImage) {
ByteArrayOutputStream bytes = new ByteArrayOutputStream();
inImage.compress(Bitmap.CompressFormat.JPEG, 100, bytes);
String path = Images.Media.insertImage(inContext.getContentResolver(), inImage, "Title", null);
return Uri.parse(path);
}
This works just amazing for Intents that require an Image URI, etc (so I know for sure the URI is valid).
But now I want to save this Image URI to a file on the SDCARD. This is more difficult because the URI does not really point at a file on the SDCARD or the app.
Will I have to create a bitmap from the URI first, and then save the Bitmap on the SDCARD or is there a quicker way (preferable one that does not require the conversion to a bitmap first).
(I've had a look at this answer, but it returns file not found - https://stackoverflow.com/a/13133974/1683141)
回答1:
The problem is that the Uri you've been given by Images.Media.insertImage()
isn't to an image file, per se. It is to a database entry in the Gallery. So what you need to do is read the data from that Uri and write it out to a new file in the external storage using this answer https://stackoverflow.com/a/8664605/772095
This doesn't require creating a Bitmap, just duplicating the data linked to the Uri into a new file.
You can get the data using an InputStream using code like:
InputStream in = getContentResolver().openInputStream(imgUri);
Update
This is completely untested code, but you should be able to do something like this:
Uri imgUri = getImageUri(this, bitmap); // I'll assume this is a Context and bitmap is a Bitmap
final int chunkSize = 1024; // We'll read in one kB at a time
byte[] imageData = new byte[chunkSize];
try {
InputStream in = getContentResolver().openInputStream(imgUri);
OutputStream out = new FileOutputStream(file); // I'm assuming you already have the File object for where you're writing to
int bytesRead;
while ((bytesRead = in.read(imageData)) > 0) {
out.write(Arrays.copyOfRange(imageData, 0, Math.max(0, bytesRead)));
}
} catch (Exception ex) {
Log.e("Something went wrong.", ex);
} finally {
in.close();
out.close();
}
来源:https://stackoverflow.com/questions/21960650/image-uri-to-file