Convert Java Map to Scala Map

不打扰是莪最后的温柔 提交于 2020-01-19 07:05:07

问题


I have a java map: java.util.Map<SomeObject, java.util.Collection<OtherObject>> and I would like to convert it to the scala map: Map[SomeObject, Set[OtherObject]]

I have used mapAsScalaMap but the result is not quite what I want, the result is: Map[SomeObject, java.util.Collection[OtherObject]]. How can I fix it to also convert the collection to a set?

NOTE: actually my original problem was to convert google's ArrayListMultimap<SomeObject, OtherObject> to a MultiMap[SomeObject, OtherObject] but since this was not possible I've split the problem. If you have a solution for the original problem, I'll also accept it as the answer.


回答1:


Edit: the recommended way is now to use JavaConverters and the .asScala method:

import scala.collection.JavaConverters._
val myScalaMap = myJavaMap.asScala.mapValues(_.asScala.toSet)

This has the advantage of not using magical implicit conversions but explicit calls to .asScala, while staying clean and consise.


The original answer with JavaConversions:

You can use scala.collection.JavaConversions to implicitly convert between Java and Scala:

import scala.collection.JavaConversions._
val myScalaMap = myJavaMap.mapValues(_.toSet)

Calling mapValues will trigger an implicit conversion from the java Map to a scala Map, and then calling toSet on the java collection with implicitly convert it to a scala collection and then to a Set.

By default, it returns a mutable Map, you can get an immutable one with an additional .toMap.

Short-ish example:

scala> val a: java.util.Map[String, java.util.Collection[String]] = new java.util.HashMap[String, java.util.Collection[String]]
a: java.util.Map[String,java.util.Collection[String]] = {}

scala> val b = new java.util.ArrayList[String]
b: java.util.ArrayList[String] = []

scala> b.add("hi")
res5: Boolean = true

scala> a.put("a", b)
res6: java.util.Collection[String] = []

scala> import scala.collection.JavaConversions._
import scala.collection.JavaConversions._

scala> val c = a.mapValues(_.toSet)
c: scala.collection.Map[String,scala.collection.immutable.Set[String]] = Map(a -> Set(hi))

scala> c.toMap
res7: scala.collection.immutable.Map[String,scala.collection.immutable.Set[String]] = Map(a -> Set(hi))



回答2:


Immutable Map myJavaMap.asScala.toMap

Mutable Map myJavaMap.asScala




回答3:


If you have to do this from java:

List<Tuple2<A, B>> tuples = javaMap.entrySet().stream()
            .map(e -> Tuple2.apply(e.getKey(), e.getValue()))
            .collect(Collectors.toList());

scala.collection.Map scalaMap = scala.collection.Map$.MODULE$.apply(JavaConversions.asScalaBuffer(tuples).toSeq());

Based on: https://stackoverflow.com/a/45373345/5209935




回答4:


You can convert the Java Map into Scala Map using the below function:

val scalaMap = javaMap.asScala;

For using this you need to import the import scala.collection.JavaConverters._ library.

Hope this helps.



来源:https://stackoverflow.com/questions/16918956/convert-java-map-to-scala-map

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