How to call a method with a separate thread in Java?

问题

let's say I have a method doWork(). How do I call it from a separate thread (not the main thread).

回答1:

Create a class that implements the Runnable interface. Put the code you want to run in the run() method - that's the method that you must write to comply to the Runnable interface. In your "main" thread, create a new Thread class, passing the constructor an instance of your Runnable, then call start() on it. start tells the JVM to do the magic to create a new thread, and then call your run method in that new thread.

public class MyRunnable implements Runnable {

    private int var;

    public MyRunnable(int var) {
        this.var = var;
    }

    public void run() {
        // code in the other thread, can reference "var" variable
    }
}

public class MainThreadClass {
    public static void main(String args[]) {
        MyRunnable myRunnable = new MyRunnable(10);
        Thread t = new Thread(myRunnable)
        t.start();
    }    
}

Take a look at Java's concurrency tutorial to get started.

If your method is going to be called frequently, then it may not be worth creating a new thread each time, as this is an expensive operation. It would probably be best to use a thread pool of some sort. Have a look at Future, Callable, Executor classes in the java.util.concurrent package.

回答2:

Thread t1 = new Thread(new Runnable() {
    @Override
    public void run() {
        // code goes here.
    }
});  
t1.start();

new Thread(new Runnable() {
     @Override
     public void run() {
          // code goes here.
     }
}).start();

new Thread(() -> {
    // code goes here.
}).start();

Executors.newSingleThreadExecutor().execute(new Runnable() {
    @Override
    public void run() {
        myCustomMethod();
    }
});

Executors.newCachedThreadPool().execute(new Runnable() {
    @Override
    public void run() {
        myCustomMethod();
    }
});

回答3:

In Java 8 you can do this with one line of code.

If your method doesn't take any parameters, you can use a method reference:

new Thread(MyClass::doWork).start();

Otherwise, you can call the method in a lambda expression:

new Thread(() -> doWork(someParam)).start();

回答4:

Another quicker option to call things (like DialogBoxes and MessageBoxes and creating separate threads for not-thread safe methods) would be to use the Lamba Expression

  new Thread(() -> {
                      "code here"
            }).start();

回答5:

Sometime ago, I had written a simple utility class that uses JDK5 executor service and executes specific processes in the background. Since doWork() typically would have a void return value, you may want to use this utility class to execute it in the background.

See this article where I had documented this utility.

回答6:

To achieve this with RxJava 2.x you can use:

Completable.fromAction(this::dowork).subscribeOn(Schedulers.io().subscribe();

The subscribeOn() method specifies which scheduler to run the action on - RxJava has several predefined schedulers, including Schedulers.io() which has a thread pool intended for I/O operations, and Schedulers.computation() which is intended for CPU intensive operations.

回答7:

If you are using at least Java 8 you can use method runAsync from class CompletableFuture

CompletableFuture.runAsync(() -> {...});

If you need to return a result use supplyAsync instead

CompletableFuture.supplyAsync(() -> 1);

来源：https://stackoverflow.com/questions/3489543/how-to-call-a-method-with-a-separate-thread-in-java

标签

java

multithreading