问题
<script language="javascript" type="text/javascript">
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var result = ajaxRequest.responseText;
}
}
ajaxRequest.open("GET", "vartest.php", true);
document.getElementById('span').innerHTML = result;
ajaxRequest.send(null);
}
回答1:
This is because Ajax is asynchronous, and result isn't set yet when you do this (plus the var makes it local to the function anyway, you'd have to remove that).
The best thing to do would be to move the innerHTML line into the readystatechange callback.
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
document.getElementById('span').innerHTML = ajaxRequest.responseText;;
}
回答2:
<script language="javascript" type="text/javascript">
//this is in the global scope
//so it's available anywhere
**var result;**
function ajaxFunction(){
var path = 'http://localhost/php/';
var fileName = 'yourCode.php';
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
} catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
} catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
} catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
// Create a function that will receive data sent from the server
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
**result = ajaxRequest.responseText;**
}
}
ajaxRequest.open("GET", path+fileName, true);
ajaxRequest.send(null);
}
</script>
回答3:
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
result = ajaxRequest.responseText;
}
}
ajaxRequest.open("GET", "vartest.php", true);
document.getElementById('span').innerHTML = result;
ajaxRequest.send(null);
}
来源:https://stackoverflow.com/questions/5050387/store-xmlhttprequest-responsetext-as-variable