A way to output pyunit test name in setup()

问题

Is there a way in python for a pyunit test to output the test it's currently running. Example:

def setUp(self):
    log.debug("Test %s Started" % (testname))

def test_example(self):
    #do stuff

def test_example2(self):
    #do other stuff

def tearDown(self):
    log.debug("Test %s Finished" % (testname))

回答1:

You can use self._testMethodName. This is inherited from the unittest.TestCase parent class.

def setUp():
    print "In method", self._testMethodName

回答2:

self.id().split('.')[-1]

You can find the Documentation at: http://docs.python.org/library/unittest.html#unittest.TestCase.id

edit: For 2.7 users, https://docs.python.org/2.7/library/unittest.html#unittest.TestCase.id

回答3:

You can usestr(self.id()).split()[4]. It could be found here http://docs.python.org/library/unittest.html#unittest.TestCase.id

来源：https://stackoverflow.com/questions/4504622/a-way-to-output-pyunit-test-name-in-setup