Python手写数字识别之路1

若如初见. 提交于 2020-01-16 00:52:54

Python入门

虽然Python是从C语言发展而来,但是我觉得和c语言区别巨大。
首先玩一个小游戏

guess

"python"

import random

counts = 3
answer = random.randint(1,10)   #生成一个随机数,guess
while counts > 0:
    temp = input("enter number ")
    guess = int(temp)

    if guess == answer:
        print("right")
        break
    else:
        if guess < answer:
            print("small")
        else:
            print("big")
        counts = counts -1

print("game over")

for

member = ['小明','弱音','狂三','光辉']
for i in member:
    print(i, len(i))
    
for i in range(0, 20, 3):  # 步进为3
    print(i)

white

while TURE:
	code

list

member = ['小明','弱音','狂三','光辉']
for i in member:
    print(i, len(i))
member.append('洛天依')
for i in member:
    print(i, len(i))
    
member.extend(['东方','丝袜'])
for i in member:
    print(i, len(i))
member.insert(1,'手写数字识别')
for i in member:
    print(i, len(i))
    
member.remove('手写数字识别')
for i in member:
    print(i)
    
del member[1]
for i in member:
    print(i)


member.pop(1)
for i in member:
    print(i)
    
member[1:3]
for i in member[1:3]:
    print(i)
    

列表

list1 = [123]
list2 = [456]
print(list1 > list2)

list1 = [123,456]
list2 = [234,123]
print(list1 > list2)
list3 = [123,456]

print((list1 < list2) and (list1 == list3))

list4 = list1 + list2
print(list4)

list3 *3
list3 +=3
123 in list3
2 not in list3

list5 = [123, ['小明','牡丹'],123]

'小明' in list5
'小明' in list5[1]

list5[1][1]

list3.count(123)

list3.index(123)
list3.index(123,4,9)
list3.reverse()

list3.sort()

sort(func,key)
list3.sort(reverse=True)

list3 = list1   #创建指针
list3 = list[:]  #拷贝


元组

tuple1 = (1,2,3,4,5,6,7,8)
print(tuple1)

temp1 = (1)
print(type(temp1))

temp2 =2,3,4
print(type(temp2))

temp3 =()
print(type(temp3))

temp4 = (1,)
print(type(temp4))

temp5 = 1,
print(type(temp4))

temp6 = ('弱音','狂三','萝莉','光辉')

temp7 = temp6[:2] + ('洛天依',) + temp6[2:]
print(temp7)

字符串

各种函数

格式化字符串

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