问题
I'm currently implement left shift using int[]
arrays in php and need to get back the decimal after operation. So I have written the following snippet to attempt conversion of binary array to decimal.
function bin2dec($bin)
{
$length = count($bin) - 1;
$sum = 0;
//convert using doubling
for($i = 0; $i < $length; $i++)
{
//use string_add if doubling bigger than int32
if($i >= 16)
{
$double = $this->string_add("$sum", "$sum");
$cr = $bin[$i];
if($cr == 0)
{
$sum = $this->string_add($sum, $double);
}
else{
return $i;//WHAT's UP??!
$add = $this->string_add($double, "$cr");
$sum = $this->string_add($sum, $add);
}
}
else{
$sum += ($sum * 2) + $bin[$i];
}
}
return $sum;
}
Now the weird problem is in the loop where $cr != 0
, $i
returns an unbelievable value already not satisfying the loop condition but I can't figure out why this is happening. Here's the rest of the relevant code.
function string_add($a, $b)
{
$lena = strlen($a); $lenb = strlen($b);
if($lena == $lenb)
{
$len = $lena - 1;//any
}
else if($lena > $lenb)
{
$b = str_pad($b, $lena, "0", STR_PAD_LEFT);
$len = $lena - 1;
}
else if($lenb > $lena){
$a = str_pad($a, $lenb, "0", STR_PAD_RIGHT);
$len = $lenb - 1;
}
$result = "";
for ($i = $len, $carry = 0; $i >= 0 || $carry != 0; $i--)
{
$add1 = $i < 0 ? 0 : $a[$i];
$add2 = $i < 0 ? 0 : $b[$i];
$add = $add1 + $add2 + $carry;
if ($add > 9) {
$carry = 1;
$add -= 10;
}
else {
$carry = 0;
}
$result .= $add;
}
return strrev($result);
}
$arr = array_pad(array(1), 62, 0);
$dec = bin2dec($arr);
return $dec;//test
I have also implemented a working version on ideone for testing. Does anyone understand why this is happening?
Thanks.
回答1:
Ok, so apparently the problem was adding more than needed and unnecessarily subtracting 1 from length in bin2dec. Here's the final working version:
<?php
class MyClass{
function bin2dec($bin)
{
$length = count($bin);
$sum = 0;
//convert using doubling
for($i = 0; $i < $length; $i++)
{
//use string_add if doubling bigger than int32
if($i >= 16)
{
$sum = $this->string_add("$sum", "$sum");
$cr = $bin[$i];
if($cr != 0){
$sum = $this->string_add($sum, "$cr");
}
}
else{
$sum += $sum + $bin[$i];
}
}
return $sum;
}
function string_add($a, $b)
{
$lena = strlen($a); $lenb = strlen($b);
if($lena == $lenb)
{
$len = $lena - 1;//any
}
else if($lena > $lenb)
{
$b = str_pad($b, $lena, "0", STR_PAD_LEFT);
$len = $lena - 1;
}
else if($lenb > $lena){
$a = str_pad($a, $lenb, "0", STR_PAD_RIGHT);
$len = $lenb - 1;
}
$result = "";
for ($i = $len, $carry = 0; $i >= 0 || $carry != 0; $i--)
{
$add1 = $i < 0 ? 0 : $a[$i];
$add2 = $i < 0 ? 0 : $b[$i];
$add = $add1 + $add2 + $carry;
if ($add > 9) {
$carry = 1;
$add -= 10;
}
else {
$carry = 0;
}
$result .= $add;
}
return strrev($result);
}
}
$man = new MyClass();
$arr = array_pad(array(1), 62, 0);
$dec = $man->bin2dec($arr);
echo $dec;
回答2:
Using strings...
function bin2dec($bin)
{
$length = count($bin);
$sum = "";
for ( $i = 0; $i < $length; $i++)
{
$sum = $sum . ( $bin[$i} == 0 ? '0' : '1');
}
return $sum;
}
function string_add($a, $b)
{
// not efficient, but obvious
$maxlen = ( strlen($a) > strlen($b) ? strlen($a) : strlen($b);
// make them both same length as longest
$a = str_pad($a, $maxlen, "0", STR_PAD_LEFT);
$b = str_pad($b, $maxlen, "0", STR_PAD_LEFT);
$result = "";
$carry = 0;
// start from the right end
for ($i = $maxlen - 1; $i >= 0; $i--)
{
$val = $a[$i] + $b[$i] + $carry;
$result = ( $val % 10 ) . $result;
$carry = $val / 10;
}
// handle final carry if present
if ( $carry > 0 )
{
$result = $carry . $result;
}
return $result;
}
$arr = array_pad(array(1), 62, 0);
$dec = bin2dec($arr);
return $dec;//test
来源:https://stackoverflow.com/questions/24346286/converting-binary-array-to-decimal-string-strange-behaviour