问题
I've been searching for this and I'm amazed I haven't found anything. Why can't I inherit a base class constructor using using declaration and add an overload in the derived class? I'm using Visual C++ 2013, the base class constructor is ignored when default-constructing b:
error C2512: 'B' : no appropriate default constructor available
I've dealt with this by re-defining the constructors, but I don't like that. This is just a minimal example, it wouldn't bother me if I had only one base class constructor.
struct A
{
A() : a(10) {}
int a;
};
struct B : A
{
using A::A;
explicit B(int a) { this->a = a; }
};
int main()
{
B b;
}
回答1:
The problem is that default-constructors are not inherited. From [class.inhctor]/p3:
For each non-template constructor in the candidate set of inherited constructors [..], a constructor is implicitly declared with the same constructor characteristics unless there is a user-declared constructor with the same signature in the complete class where the using-declaration appears or the constructor would be a default, copy, or move constructor for that class.
You also have a user-declared constructor that suppresses the creation of an implicit default-constructor. Just add a defaulted one to make it work:
B() = default;
来源:https://stackoverflow.com/questions/38685216/constructor-of-the-base-is-not-made-available-by-the-using-declaration