Show Hide div if, if statement is true

问题

My code works to a point. What I want is that when this if statement is false, the <div> doesn't show

<?php
    $query3 = mysql_query($query3);
    $numrows = mysql_num_rows($query3);
    if ($numrows > 0) {
        $fvisit = mysql_fetch_array($result3);
    }
    else {
    }
?>

回答1:

You can use css or js for hiding a div. In else statement you can write it as:

else{
?>
<style type="text/css">#divId{
display:none;
}</style>
<?php
}

Or in jQuery

else{
?>
<script type="text/javascript">$('#divId').hide()</script>
<?php
}

Or in javascript

else{
?>
<script type="text/javascript">document.getElementById('divId').style.display = 'none';</script>
<?php
}

回答2:

This does not need jquery, you could set a variable inside the if and use it in html or pass it thru your template system if any

<?php
$showDivFlag=false
$query3 = mysql_query($query3);
$numrows = mysql_num_rows($query3);
if ($numrows > 0){
    $fvisit = mysql_fetch_array($result3);
    $showDivFlag=true;
 }else {

 }

?>

later in html

  <div id="results" <?php if ($showDivFlag===false){?>style="display:none"<?php } ?>>

回答3:

Use show/hide method as below

$("div").show();//To Show

$("div").hide();//To Hide

回答4:

A fresh look at this(possibly)
in your php:

else{
      $hidemydiv = "hide";
}

---

And then later in your html code:

<div class='<?php echo $hidemydiv ?>' > maybe show or hide this</div>

in this way your php remains quite clean

回答5:

<?php
$divStyle=''; // show div

// add condition
if($variable == '1'){
  $divStyle='style="display:none;"'; //hide div
}

print'<div '.$divStyle.'>Div to hide</div>';
?>

来源：https://stackoverflow.com/questions/7020873/show-hide-div-if-if-statement-is-true