Match only entire words with LIKE?

半腔热情 提交于 2019-11-27 13:12:25

How about split it into four parts -

[MyColumn] Like '% doc %' 
OR [MyColumn] Like '% doc' 
OR [MyColumn] Like 'doc %' 
OR [MyColumn] = 'doc'

Edit: An alternate approach (only for ascii chars) could be:

'#'+[MyColumn]+'#' like '%[^a-z0-9]doc[^a-z0-9]%'

(You may want to take care of any special char as well)

It doesn't look like, but you may want to explore Full Text Search and Contains, in case that's more suitable for your situation.

See: - MSDN: [ ] (Wildcard - Character(s) to Match) (Transact-SQL)

WHERE (@string LIKE 'doc %' OR @string LIKE '% doc' OR @string LIKE '% doc %' OR @string = 'doc')

you can just use below condition:

(' '+YOUR_FIELD_NAME+' ') like '% doc %'

it works faster than other solutions.

You could use some ORs, LIKE '% doc %' OR LIKE 'doc %' OR LIKE '% doc' OR LIKE 'doc'

None of the answers worked for me (SQL Server 2008 R2).

But I managed to get it to work using somewhat of the answers shown below..

SELECT * FROM myTable AS v
WHERE v.Note LIKE '%[^a-zA-Z0-9]CONTainers[^a-zA-Z0-9]%'

Note: v.Note is a TEXT data type

This worked for me with the following samples..

  • containers
  • CONTAINERS
  • conTaInERS

But not when the word 'containers' was surrounded by other letters or numerics..

  • 001containers001
  • AAcontainersAA

Which is what the OP asked for in the first place.

What about NOT LIKE '%doc%'?

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