问题
I use below statment to get html string:
import urllib3
url ='http://urllib3.readthedocs.org/'
http_pool = urllib3.connection_from_url(url)
r = http_pool.urlopen('GET',url)
print (r.data)
But the output is :
b'<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "b'\n<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN"\n "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">\n\n\n<html xmlns="http://www.w3.org/1999/xhtml">\n <head>\n <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />\n \n\n .......................................\n</script>\n\n\n\n </body>\n</html>''
How can I get a raw html string?
回答1:
The anwser is print (r.data.decode('utf-8'))
But this statment will break in sublime text 2.
Because of this issue.
When I use IDLE,the output will be fine.
来源：https://stackoverflow.com/questions/17257912/how-to-print-raw-html-string-using-urllib3