问题
I'm trying to match URLs with wildcards in them to actual URLs. For example:
http://*google.com/*
Needs to match
http://maps.google.com
And
http://www.google.com/maps
What would be the best way of going about this?
I've tried using a regular expression and that works fine when I manually program it but I'm not sure whether it's possible to dynamically generate regular expressions or if that would be the best practice in this situation.
/(http|https):\/\/.*\.?google\.com\/?.*/i
Thanks very much.
回答1:
Replace all occurrences of *
in the pattern with [^ ]*
- it matches a sequence of zero or more non-space characters.
Thus http://*google.com/*
will become http://[^ ]*google.com/[^ ]*
Here is a regular expression to do the task:
regex = urlPattern.replace(/\*/g, "[^ ]*");
回答2:
Generating a regex is probably the right way, but is gets more complicated than simply replacing the asterisks.
For example, your pattern http://*google.com/*
should not match http://www.malicioushacker.org/1337/google.com/maps
.
回答3:
If you want to see a well tested library for extracting parts of a URI, I would check out Google Closure Library's goog.uri.utils methods.
https://github.com/google/closure-library/blob/8e44fb343fff467938f9476ba7f727c6acac76d8/closure/goog/uri/utils.js#L187
Here's the regex that does the heavy lifting:
goog.uri.utils.splitRe_ = new RegExp(
'^' +
'(?:' +
'([^:/?#.]+)' + // scheme - ignore special characters
// used by other URL parts such as :,
// ?, /, #, and .
':)?' +
'(?://' +
'(?:([^/?#]*)@)?' + // userInfo
'([\\w\\d\\-\\u0100-\\uffff.%]*)' + // domain - restrict to letters,
// digits, dashes, dots, percent
// escapes, and unicode characters.
'(?::([0-9]+))?' + // port
')?' +
'([^?#]+)?' + // path
'(?:\\?([^#]*))?' + // query
'(?:#(.*))?' + // fragment
'$');
来源:https://stackoverflow.com/questions/3117218/matching-url-with-wildcards