Conditional sorting in MySQL?

问题

I have "tasks" table with 3 fields:

1. date
2. priority (0,1,2)
3. done (0,1)

What I am trying to achieve is with the whole table sorted by done flag, tasks that are not done should be sorted by priority, while tasks that are done should be sorted by date:

1. Select * from tasks order by done asc
2. If done=0 additionally order by priority desc
3. If done=1 additionally order by date desc

Is it possible to do this in MySQL without unions?

Thanks.

回答1:

You could try ORDER BY (done asc, aux desc) where aux is computed with a CASE to yield either priority or date based on the value of done (you may have to cast them to the same type to fit in the same expression, e.g. cast the date to a suitable integer day number).

For example:

SELECT * FROM tab
ORDER BY done desc,
         case done
             when 0 then prio 
             else to_days(thedate)
         end desc;

回答2:

Taken from Alex Martelli just shortened a bit with IF() and fixed the ASC/DESC ordering

SELECT * FROM tab
ORDER BY done ASC, IF(done, to_days(thedate), prio) DESC;

来源：https://stackoverflow.com/questions/1084362/conditional-sorting-in-mysql