问题
I have a folder that is my animation/game, and in the folder is the .pyw file and a .wav music file. I have
import wave
wave.open()
and I don't know what to put in the parenthesis. I know it is supposed to be the filename, but someone might install the game in an unknown directory. How do I access the local folder through the filename?
The files are in the same folder, and the music is named "Music.wav".
回答1:
A common way this is done is by using the path of the current module, which is automatically available in the predefined__file__
variable, to determine the path to the file in the subdirectory:
import os
import wave
mydir = os.path.dirname(__file__)
subdir = 'sounds'
wavefilepath = os.path.join(mydir, subdir, 'Music.wav')
wave.open(wavefilepath)
来源:https://stackoverflow.com/questions/27583041/how-do-i-access-a-local-folder-through-its-filename