问题
I've been trying to figure out what exactly is happening here. I'm just trying to figure out what the 2 lines are doing that I've commented on below. I found this program that doesn't declare the full dimensions of the array (instead of new int[10][5]; it just decides to not declare it by saying 'new int[10][];' It's like the 2nd array length doesn't matter (changing it to 1 or 100 doesn't affect the output).
int[][] tri = new int[10][]; //this lack of giving the size of the 2nd array is strange
for (int r=0; r<tri.length; r++) {
tri[r] = new int[r+1]; //I'm not sure what this line is doing really
}
for (int r=0; r<tri.length; r++) {
for (int a=0; a<tri[r].length; a++) {
System.out.print(tri[r][a]);
}
System.out.println();
}
回答1:
The first line makes an array of int arrays. There are 10 slots for int arrays created.
The third line creates a new int array and puts it in one of the slots you made at first. The new int array has r+1 spaces for ints in it.
So, the int array in position 0 will have 1 slot for an int. The int array in position 1 will have 2 slots for an int. The overall shape will be:
[
[0],
[0,0],
[0,0,0],
...,
[0,0,0,0,0,0,0,0,0,0]
]
which is hinted at with the variable name tri (it looks like a triangle)
回答2:
All new int[10][] is declaring is an array of size 10, containing null arrays.
In the for loop, the null arrays are being instantiated into ever increasing array sizes.
回答3:
It makes more sense if you think of a multidimensional array as an array of arrays:
int [][] tri = new int[10][]; // This is an array of 10 arrays
tri[r] = new int[r+1]; // This is setting the r'th array to
// a new array of r+1 ints
回答4:
It's simply declaring an array of 10 arrays. The lengths of each of those "sub" arrays can all be different.
回答5:
it's not lacking, it's basically not setting a specific amount, it isn't required because it can have many fields
and the second line
tri[r] = new int[r+1];
is setting all the fields to not null
来源:https://stackoverflow.com/questions/9896968/java-declaring-a-multidimensional-array-without-specifying-the-size-of-the-arra