Regex in KornShell | 易学教程

问题

I am trying to check whether a variable is exactly two numbers but I can not seem to figure it out.

How do you do check regular expressions (regex) in KornShell (ksh)?

I have tried:

if [[ $month =~ "[0-9]{2}" ]]
if [[ $month = _[0-9]{2}_ ]]

I have not been able to find any docs on it.

Any insight?

回答1:

case $month in
    [0-9][0-9]) echo "ok";;
    *) echo "no";;
esac

should work.

If you need full regexp search, you can use egrep like this:

if echo $month | egrep -q '^[0-9]{2}$'
then
    echo "ok"
else
    echo "no"
fi

回答2:

Ksh has supported limited extended patterns since ksh88, using the

special '(' pattern ')'

syntax.

In ksh88, the 'special' character prefixes change the number of matches expected:

'*' for zero or more matches
'+' at least one match
'@' for exactly one match
'?' for zero or one matches
'!' for negation

In ksh93, this was expanded with

'{' min ',' max '}'

to express an exact range:

for w in 1423 12 "" abc 23423 9 33 3  333
do
  [[ $w == {1,3}(\d) ]] && print $w has between 1 and three digits
  [[ $w == {2}(\d) ]] && print $w has exactly two digits
done

And finally, you can have perl-like clutter with '~', which introduces a whole new class of extensions,including full regular expressions with:

'~(E)( regex )'

More examples can be found in Finnbarr P. Murphy's blog

回答3:

Where I come from, this is more likely to validate numeric months:

if (( $month >= 1 && $month <= 12 ))

[[ $month =~ ^([1-9]|1[012])$ ]]

or to include a leading zero for single-digit months:

[[ $month =~ ^(0[1-9]|1[012])$ ]]

回答4:

ksh does not use regular expressions; it uses a simpler but still quite useful language called "shell globbing patterns". The key ideas are

Classes like [0-9] or [chly] match any character in the class.
The . is not a special character; it matches only ..
The ? matches any single character.
The * matches any sequence of characters.
Unlike regular expressions, shell globbing patterns must match the entire word, so it works as if it were a regexp it would always start with ^ and end with $.

Globbing patterns are not as powerful as regular expressions, but they are much easier to read, and they are very convenient for matching filenames and simple words. The case construct is my favorite for matching but there are others.

As already noted by Alok you probably want

case $number in
  [0-9][0-9]) success ;;
  *) failure;;
esac

Although possibly you might prefer not to match a two-digit number with initial zero, so prefer [1-9][0-9].

回答5:

you can try this as well

$ month=100
$ [[ $month == {1,2}([0-9]) ]] && echo "ok" || echo "no"
no
$ [[ $month == [0-9][0-9] ]] && echo "ok" || echo "no"
no
$ month=10
$ [[ $month == {1,2}([0-9]) ]] && echo "ok" || echo "no"
ok
$ [[ $month == [0-9][0-9] ]] && echo "ok" || echo "no"
ok

来源：https://stackoverflow.com/questions/2121394/regex-in-kornshell

标签

regex

shell

unix

ksh